From mboxrd@z Thu Jan 1 00:00:00 1970 Return-path: Received: from mail-we0-f174.google.com ([74.125.82.174]:34017 "EHLO mail-we0-f174.google.com" rhost-flags-OK-OK-OK-OK) by vger.kernel.org with ESMTP id S1750810Ab2CPVYc (ORCPT ); Fri, 16 Mar 2012 17:24:32 -0400 Received: by wejx9 with SMTP id x9so4322064wej.19 for ; Fri, 16 Mar 2012 14:24:31 -0700 (PDT) Message-ID: <4F63AF8D.3060005@unixindia.com> Date: Fri, 16 Mar 2012 21:24:29 +0000 From: Bhasker C V MIME-Version: 1.0 To: linux-media@vger.kernel.org Subject: Bit rate of a transport stream Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: 7bit Sender: linux-media-owner@vger.kernel.org List-ID: Hi all, In finding the bit rate of a transport stream as a whole, I had a doubt if someone can help me please I did try to google but could not get any definite information on this topic Say I have 2 programs in a transport stream each with 1 audio and 1 video Can I safely assume the total bitrate of the stream is the combined bitrate of program 1 ES rate and progam 2 ES rate ? If this is the case will the audio PIDs should also be taken into account for caculating the total bitrate of the stream ? Program 1 -> PIDA(audio), PIDB(video) Program 2 -> PIDC(audio), PIDD(video) bitrate = ES rate of PIDA + PIDB + PIDC + PIDD ? or is there any other easier way to find the bitrate of a MPEG transport stream ? thanks -- Bhasker C V