Re: [PATCH 1/1] sched/eas: introduce system-wide overutil indicator

[Quentin Perret <qperret@qperret.net>]

Hi,

Could you please CC me on later versions of this ? I'm interested.

On Thursday 19 Sep 2019 at 15:20:22 (+0800), YT Chang wrote:
> When the system is overutilization, the load-balance crossing
> clusters will be triggered and scheduler will not use energy
> aware scheduling to choose CPUs.
> 
> The overutilization means the loading of  ANY CPUs
> exceeds threshold (80%).
> 
> However, only 1 heavy task or while-1 program will run on highest
> capacity CPUs and it still result to trigger overutilization. So
> the system will not use Energy Aware scheduling.
> 
> To avoid it, a system-wide over-utilization indicator to trigger
> load-balance cross clusters.
> 
> The policy is:
> 	The loading of "ALL CPUs in the highest capacity"
> 						exceeds threshold(80%) or
> 	The loading of "Any CPUs not in the highest capacity"
> 						exceed threshold(80%)
> 
> Signed-off-by: YT Chang <yt.chang@mediatek.com>

Right, so we originally went for the simpler implementation because in
general when you have the biggest CPUs of the system running flat out at
max freq, the micro-optimizations for energy on littles don't matter all
that much. Is there a use-case where you see a big difference ?

A second thing is RT pressure. If a big CPU is used at 50% by a CFS task
and 50% by RT, we should mark it overutilized. Otherwise EAS will think
the CFS task is 50% and try to down-migrate it. But the truth is, we
dont know the size of the task ... So, I believe your patch breaks that
ATM.

And there is a similar problem with misfit. That is, a task running flat
out on a big CPU will be flagged as misfit, even if there is nothing we
can do about (we can't up-migrate it for obvious reasons). So perhaps we
should look at a common solution for both issues, if deemed useful.

> ---
>  kernel/sched/fair.c | 76 +++++++++++++++++++++++++++++++++++++++++++++--------
>  1 file changed, 65 insertions(+), 11 deletions(-)
> 
> diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c
> index 036be95..f4c3d70 100644
> --- a/kernel/sched/fair.c
> +++ b/kernel/sched/fair.c
> @@ -5182,10 +5182,71 @@ static inline bool cpu_overutilized(int cpu)
>  static inline void update_overutilized_status(struct rq *rq)
>  {
>  	if (!READ_ONCE(rq->rd->overutilized) && cpu_overutilized(rq->cpu)) {
> -		WRITE_ONCE(rq->rd->overutilized, SG_OVERUTILIZED);
> -		trace_sched_overutilized_tp(rq->rd, SG_OVERUTILIZED);
> +		if (capacity_orig_of(cpu_of(rq)) < rq->rd->max_cpu_capacity) {
> +			WRITE_ONCE(rq->rd->overutilized, SG_OVERUTILIZED);
> +			trace_sched_overutilized_tp(rq->rd, SG_OVERUTILIZED);
> +		}
>  	}
>  }
> +
> +static
> +void update_system_overutilized(struct sched_domain *sd, struct cpumask *cpus)
> +{
> +	unsigned long group_util;
> +	bool intra_overutil = false;
> +	unsigned long max_capacity;
> +	struct sched_group *group = sd->groups;
> +	struct root_domain *rd;
> +	int this_cpu;
> +	bool overutilized;
> +	int i;
> +
> +	this_cpu = smp_processor_id();
> +	rd = cpu_rq(this_cpu)->rd;
> +	overutilized = READ_ONCE(rd->overutilized);
> +	max_capacity = rd->max_cpu_capacity;
> +
> +	do {
> +		group_util = 0;
> +		for_each_cpu_and(i, sched_group_span(group), cpus) {
> +			group_util += cpu_util(i);
> +			if (cpu_overutilized(i)) {
> +				if (capacity_orig_of(i) < max_capacity) {

This is what breaks things with RT pressure I think.

> +					intra_overutil = true;
> +					break;
> +				}
> +			}
> +		}
> +
> +		/*
> +		 * A capacity base hint for over-utilization.
> +		 * Not to trigger system overutiled if heavy tasks
> +		 * in Big.cluster, so
> +		 * add the free room(20%) of Big.cluster is impacted which means
> +		 * system-wide over-utilization,
> +		 * that considers whole cluster not single cpu
> +		 */
> +		if (group->group_weight > 1 && (group->sgc->capacity * 1024 <
> +						group_util * capacity_margin)) {
> +			intra_overutil = true;
> +			break;
> +		}

What if we have only one big MC domain with both big and little CPUs and
no DIE ? Say you have 4 big tasks, 4 big CPUs, 4 little CPUs (idle).
You'll fail to mark the system overutilized no ?

> +
> +		group = group->next;
> +
> +	} while (group != sd->groups && !intra_overutil);
> +
> +	if (overutilized != intra_overutil) {
> +		if (intra_overutil == true) {
> +			WRITE_ONCE(rd->overutilized, SG_OVERUTILIZED);
> +			trace_sched_overutilized_tp(rd, SG_OVERUTILIZED);
> +		} else {
> +			WRITE_ONCE(rd->overutilized, 0);
> +			trace_sched_overutilized_tp(rd, 0);
> +		}
> +	}
> +}
> +
>  #else
>  static inline void update_overutilized_status(struct rq *rq) { }
>  #endif
> @@ -8242,15 +8303,6 @@ static inline void update_sd_lb_stats(struct lb_env *env, struct sd_lb_stats *sd
>  
>  		/* update overload indicator if we are at root domain */
>  		WRITE_ONCE(rd->overload, sg_status & SG_OVERLOAD);
> -
> -		/* Update over-utilization (tipping point, U >= 0) indicator */
> -		WRITE_ONCE(rd->overutilized, sg_status & SG_OVERUTILIZED);
> -		trace_sched_overutilized_tp(rd, sg_status & SG_OVERUTILIZED);
> -	} else if (sg_status & SG_OVERUTILIZED) {
> -		struct root_domain *rd = env->dst_rq->rd;
> -
> -		WRITE_ONCE(rd->overutilized, SG_OVERUTILIZED);
> -		trace_sched_overutilized_tp(rd, SG_OVERUTILIZED);
>  	}
>  }
>  
> @@ -8476,6 +8528,8 @@ static struct sched_group *find_busiest_group(struct lb_env *env)
>  	 */
>  	update_sd_lb_stats(env, &sds);
>  
> +	update_system_overutilized(env->sd, env->cpus);
> +
>  	if (sched_energy_enabled()) {
>  		struct root_domain *rd = env->dst_rq->rd;
>  
> -- 
> 1.9.1
>