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From: Jeff Baitis <baitisj@evolution.com>
To: Pete Popov <ppopov@mvista.com>
Cc: linux-mips@linux-mips.org
Subject: arch/mips/au1000/common/irq.c
Date: Thu, 13 Mar 2003 10:47:04 -0800	[thread overview]
Message-ID: <20030313104704.V20129@luca.pas.lab> (raw)

Pete:

I've got a question concerning irq.c. In intc0_req0_irqdispatch() (linux_2_4
branch) on lines 545 thru 552, the code reads:

      for (i=0; i<32; i++) {
          if ((intc0_req0 & (1<<i))) {
              intc0_req0 &= ~(1<<i);
              do_IRQ(irq, regs);
              break;
          }
          irq++;
      }

My question is: why do we increment i and irq independently?
Why doesn't the code read:

      for (i=0; i<32; i++) {
          if ((intc0_req0 & (1<<i))) {
              intc0_req0 &= ~(1<<i);
              do_IRQ(i, regs);
              break;
          }
      }

Thanks for your help!

-Jeff





-- 
         Jeffrey Baitis - Associate Software Engineer

                    Evolution Robotics, Inc.
                     130 West Union Street
                       Pasadena CA 91103

 tel: 626.535.2776  |  fax: 626.535.2777  |  baitisj@evolution.com 

             reply	other threads:[~2003-03-13 18:47 UTC|newest]

Thread overview: 5+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2003-03-13 18:47 Jeff Baitis [this message]
2003-03-13 18:50 ` arch/mips/au1000/common/irq.c Dan Malek
2003-03-13 22:13   ` arch/mips/au1000/common/irq.c Jeff Baitis
2003-03-13 22:25     ` arch/mips/au1000/common/irq.c Jeff Baitis
2003-03-13 18:59 ` arch/mips/au1000/common/irq.c Pete Popov

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