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From: Andrew Morton <akpm@linux-foundation.org>
To: Glauber Costa <glommer@parallels.com>,
	linux-mm@kvack.org, cgroups@vger.kernel.org, devel@openvz.org,
	kamezawa.hiroyu@jp.fujitsu.com, netdev@vger.kernel.org,
	Tejun Heo <tj@kernel.org>, Li Zefan <lizefan@huawei.com>,
	Johannes Weiner <hannes@cmpxchg.org>,
	Michal Hocko <mhocko@suse.cz>, David Miller <davem@davemloft.net>,
	Joe Perches <joe@perches.com>
Subject: Re: [PATCH v6 2/2] decrement static keys on real destroy time
Date: Tue, 22 May 2012 16:11:07 -0700	[thread overview]
Message-ID: <20120522161107.4ab99a68.akpm@linux-foundation.org> (raw)
In-Reply-To: <20120522154610.f2f9b78e.akpm@linux-foundation.org>

On Tue, 22 May 2012 15:46:10 -0700
Andrew Morton <akpm@linux-foundation.org> wrote:

> > +static inline bool memcg_proto_active(struct cg_proto *cg_proto)
> > +{
> > +	return cg_proto->flags & (1 << MEMCG_SOCK_ACTIVE);
> > +}
> > +
> > +static inline bool memcg_proto_activated(struct cg_proto *cg_proto)
> > +{
> > +	return cg_proto->flags & (1 << MEMCG_SOCK_ACTIVATED);
> > +}
> 
> Here, we're open-coding kinda-test_bit().  Why do that?  These flags are
> modified with set_bit() and friends, so we should read them with the
> matching test_bit()?
> 
> Also, these bool-returning functions will return values other than 0
> and 1.  That probably works OK and I don't know what the C standards
> and implementations do about this.  But it seems unclean and slightly
> risky to have a "bool" value of 32!  Converting these functions to use
> test_bit() fixes this - test_bit() returns only 0 or 1.
> 
> test_bit() is slightly more expensive than the above.  If this is
> considered to be an issue then I guess we could continue to use this
> approach.  But I do think a code comment is needed, explaining and
> justifying the unusual decision to bypass the bitops API.  Also these
> functions should tell the truth and return an "int" type.

Joe corrected (and informed) me:

: 6.3.1.2p1:
: 
: "When any scalar value is converted to _Bool, the result is 0
: if the value compares equal to 0; otherwise, the result is 1."

So the above functions will be given compiler-generated scalar-to-boolean
conversion.

test_bit() already does internal scalar-to-boolean conversion.  The
compiler doesn't know that, so if we convert the above functions to use
test_bit(), we'll end up performing scalar-to-boolean-to-boolean
conversion, which is dumb.

I assume that a way of fixing this is to change test_bit() to return
bool type.  That's a bit scary.

A less scary way would be to add a new

	bool test_bit_bool(int nr, const unsigned long *addr);

which internally calls test_bit() but somehow avoids the
compiler-generated conversion of the test_bit() return value into a
bool.  I haven't actually thought of a way of doing this ;)

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  reply	other threads:[~2012-05-22 23:11 UTC|newest]

Thread overview: 7+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2012-05-22 10:25 [PATCH v6 0/2] fix static_key disabling problem in memcg Glauber Costa
2012-05-22 10:25 ` [PATCH v6 1/2] Always free struct memcg through schedule_work() Glauber Costa
2012-05-22 10:25 ` [PATCH v6 2/2] decrement static keys on real destroy time Glauber Costa
2012-05-22 22:46   ` Andrew Morton
2012-05-22 23:11     ` Andrew Morton [this message]
2012-05-23  9:16     ` Glauber Costa
2012-05-23 20:33       ` Andrew Morton

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