K9F5608U0B-YIB0000: 528 byte in page, or 512?

K9F5608U0B-YIB0000: 528 byte in page, or 512?

[A.L. Klyutchenya]

I try to use the microcircuits K9F5608U0B-YIB0000 from Samsung. 
Herewith, size of the page size of this chip is 512 + 16 bytes 
(528). When I write the image of the disk on chip, me it is 
necessary to write all bytes consecutively? Or only 512 on each 
page, but remained 16 not to use?
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Re: K9F5608U0B-YIB0000: 528 byte in page, or 512?

[Charles Manning]

This is NAND flash. Do not try to treat it as NOR flash.
Use it with mtd/nand  and use YAFFS or JFFS2 file system.

You must write NAND in whole pages, not on a per-byte basis.

On Tue, 01 Apr 2003 10:07, A.L. Klyutchenya wrote:
> I try to use the microcircuits K9F5608U0B-YIB0000 from Samsung.
> Herewith, size of the page size of this chip is 512 + 16 bytes
> (528). When I write the image of the disk on chip, me it is
> necessary to write all bytes consecutively? Or only 512 on each
> page, but remained 16 not to use?

Re: K9F5608U0B-YIB0000: 528 byte in page, or 512?

[A.L. Klyutchenya]

Dear sir,
Thank you for quick answer.

1 Апрель 2003 07:36, Charles Manning написал:
> This is NAND flash. Do not try to treat it as NOR flash.
> Use it with mtd/nand  and use YAFFS or JFFS2 file system.

I want to write the first image, for booting system. I create 
this image (with kernel, MTD & Co). I have a possibility his 
write. Herewith: I have an physical access to page: size 
256+256+16, and block on 32 pages. While NO MTD and NO kernel!

> You must write NAND in whole pages, not on a per-byte basis.

I understand that page it is necessary to write, but what bring 
the first image: chain on 512+512.... or 512+16 free + 512+16 
free...

As even so write? :-) (to hrdware-level)

> On Tue, 01 Apr 2003 10:07, A.L. Klyutchenya wrote:
> > I try to use the microcircuits K9F5608U0B-YIB0000 from
> > Samsung. Herewith, size of the page size of this chip is 512
> > + 16 bytes (528). When I write the image of the disk on
> > chip, me it is necessary to write all bytes consecutively?
> > Or only 512 on each page, but remained 16 not to use?

-- 
ВсехБлаг!      
      ____   __
     /   |  / / А. Л. Клютченя
    / /| | / /  (asoneofus)
   / /_| |/ /   mail:   asoneofus@kde.ru
  / ____  _ \   www:    http://www.qt.kde.ru
 / /   | | \ \  icq:    113679387
/_/    |_|  \_\ 

Re: K9F5608U0B-YIB0000: 528 byte in page, or 512?

[Thomas Gleixner]

On Tuesday 01 April 2003 13:02, A.L. Klyutchenya wrote:
> Dear sir,
> Thank you for quick answer.
>
> 1 Апрель 2003 07:36, Charles Manning написал:
> > This is NAND flash. Do not try to treat it as NOR flash.
> > Use it with mtd/nand  and use YAFFS or JFFS2 file system.
>
> I want to write the first image, for booting system. I create
> this image (with kernel, MTD & Co). I have a possibility his
> write. Herewith: I have an physical access to page: size
> 256+256+16, and block on 32 pages. While NO MTD and NO kernel!
>
> > You must write NAND in whole pages, not on a per-byte basis.
>
> I understand that page it is necessary to write, but what bring
> the first image: chain on 512+512.... or 512+16 free + 512+16
> free...
>
> As even so write? :-) (to hrdware-level)
Please read http://linux-mtd.infraded.org/tech/nand.html

-- 
Thomas
________________________________________________________________________
linutronix - competence in embedded & realtime linux
http://www.linutronix.de
mail: tglx@linutronix.de

Re: K9F5608U0B-YIB0000: 528 byte in page, or 512?

[A.L. Klyutchenya]

2 Апрель 2003 14:28, Thomas Gleixner написал:
> On Tuesday 01 April 2003 13:02, A.L. Klyutchenya wrote:
> > Dear sir,
> > Thank you for quick answer.
> >
> > 1 Апрель 2003 07:36, Charles Manning написал:
> > > This is NAND flash. Do not try to treat it as NOR flash.
> > > Use it with mtd/nand  and use YAFFS or JFFS2 file system.
> >
> > I want to write the first image, for booting system. I
> > create this image (with kernel, MTD & Co). I have a
> > possibility his write. Herewith: I have an physical access
> > to page: size 256+256+16, and block on 32 pages. While NO
> > MTD and NO kernel!
> >
> > > You must write NAND in whole pages, not on a per-byte
> > > basis.
> >
> > I understand that page it is necessary to write, but what
> > bring the first image: chain on 512+512.... or 512+16 free +
> > 512+16 free...
> >
> > As even so write? :-) (to hrdware-level)
>
> Please read http://linux-mtd.infraded.org/tech/nand.html

I read, and don't find answer.

1) make jffs2 image: correct erase block-size for NAND (512+16 
page x 32) is 0x4200 or (512 page x 32) 0x4000?

2) for writing jffs2 image to NAND use only 512byte space on each 
page, or 512+16?

-- 
ВсехБлаг!      
      ____   __
     /   |  / / А. Л. Клютченя
    / /| | / /  (asoneofus)
   / /_| |/ /   mail:   asoneofus@kde.ru
  / ____  _ \   www:    http://www.qt.kde.ru
 / /   | | \ \  icq:    113679387
/_/    |_|  \_\ 

Re: K9F5608U0B-YIB0000: 528 byte in page, or 512?

[Charles Manning]

[snip]
> > >
> > > I understand that page it is necessary to write, but what
> > > bring the first image: chain on 512+512.... or 512+16 free +
> > > 512+16 free...
> > >
> > > As even so write? :-) (to hrdware-level)
> >
> > Please read http://linux-mtd.infraded.org/tech/nand.html
>
> I read, and don't find answer.
>
> 1) make jffs2 image: correct erase block-size for NAND (512+16
> page x 32) is 0x4200 or (512 page x 32) 0x4000?

The eraseure size is 0x4000. 
>
> 2) for writing jffs2 image to NAND use only 512byte space on each
> page, or 512+16?

The 512-byte part is written by the write function and the 16 bit "spare" or 
"out of band"  area is written with the write_oob function.

-- Charles