From mboxrd@z Thu Jan  1 00:00:00 1970
From: ichi@ihug.co.nz
Subject: Re: what's ${1##*/}
Date: Sat, 21 Dec 2002 14:52:45 +0000
Sender: linux-newbie-owner@vger.kernel.org
Message-ID: <3E04803D.D79BC7E@ihug.co.nz>
References: <20021221084841.659D.WOLFGANG127JP@ybb.ne.jp>
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To: wolfgang <wolfgang127jp@ybb.ne.jp>
Cc: linux-newbie@vger.kernel.org

wolfgang wrote:
> 
> I found the statement below in killproc() of 
> /etc/init.d/functions script.
> 
> base=${1##*/}

This is a bash structure used to remove parts of a 
variable.  The variable is $1.  The ##*/ means that 
everything before the last / is removed.  Therefore,
if $1 is the full pathname of a file, $base will be
the filename (without the path).

Cheers,
Steven

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