From: Prarit Bhargava <prarit@redhat.com>
To: linux-pm@vger.kernel.org
Cc: Prarit Bhargava <prarit@redhat.com>,
Thomas Renninger <trenn@suse.com>,
Stafford Horne <shorne@gmail.com>, Shuah Khan <shuah@kernel.org>
Subject: [PATCH] cpupower: Fix no-rounding MHz frequency output
Date: Fri, 3 Mar 2017 06:26:46 -0500 [thread overview]
Message-ID: <1488540406-13738-1-git-send-email-prarit@redhat.com> (raw)
'cpupower frequency-info -ln' returns kHz values on systems with MHz range
minimum CPU frequency range. For example, on a 800MHz to 4.20GHz system
the command returns
hardware limits: 800000 MHz - 4.200000 GHz
The value of speed passed into print_speed is in kHz, so divide speed by
1000 in the MHz else-if section to get MHz.
Signed-off-by: Prarit Bhargava <prarit@redhat.com>
Cc: Thomas Renninger <trenn@suse.com>
Cc: Stafford Horne <shorne@gmail.com>
Cc: Shuah Khan <shuah@kernel.org>
---
tools/power/cpupower/utils/cpufreq-info.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/tools/power/cpupower/utils/cpufreq-info.c b/tools/power/cpupower/utils/cpufreq-info.c
index 3e701f0e9c14..fe7c25147b3a 100644
--- a/tools/power/cpupower/utils/cpufreq-info.c
+++ b/tools/power/cpupower/utils/cpufreq-info.c
@@ -94,7 +94,7 @@ static void print_speed(unsigned long speed)
printf("%u.%06u GHz", ((unsigned int) speed/1000000),
((unsigned int) speed%1000000));
else if (speed > 100000)
- printf("%u MHz", (unsigned int) speed);
+ printf("%u MHz", (unsigned int) speed/1000);
else if (speed > 1000)
printf("%u.%03u MHz", ((unsigned int) speed/1000),
(unsigned int) (speed%1000));
--
1.7.9.3
reply other threads:[~2017-03-03 11:28 UTC|newest]
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