Re: why partition arrays?

[martin f krafft <madduck@madduck.net>]

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also sprach Doug Ledford <dledford@redhat.com> [2006.10.18.1526 +0200]:
> There are a couple reasons I can think.

Thanks for your elaborate response. If you don't mind, I shall link
to it from the FAQ.

I have one other question: do partitionable and traditional arrays
actually differ in format? Put differently: can I assemble
a traditional array as a partitionable one simply by specifying:

  mdadm --create ... /dev/md0 ...
  mdadm --stop /dev/md0
  mdadm --assemble --auto=part ... /dev/md0 ...

? Or do the superblocks actually differ?

Thanks,

-- 
martin;              (greetings from the heart of the sun.)
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