linux-raid.vger.kernel.org archive mirror
 help / color / mirror / Atom feed
* unknown partition table starting with 2.6.28
@ 2010-01-15 23:58 Timothy D. Lenz
  2010-01-16 12:43 ` John Robinson
  0 siblings, 1 reply; 6+ messages in thread
From: Timothy D. Lenz @ 2010-01-15 23:58 UTC (permalink / raw)
  To: linux-raid

I am trying to update my kernel from 2.6.26.8 to the current .32. 
Starting at .27 I get an acpi conflict:

ACPI: Power Button (CM) [PWRB]
i2c-adapter i2c-0: nForce2 SMBus adapter at 0x1c00
ACPI: I/O resource nForce2_smbus [0x1c40-0x1c7f] conflicts with ACPI 
region SM01 [0x1c40-0x1c45]
ACPI: Device needs an ACPI driver
i2c-adapter i2c-1: nForce2 SMBus adapter at 0x1c40
ACPI: Expecting a [Reference] package element, found type 0
thermal LNXTHERM:01: registered as thermal_zone0

Starting with .28 I am getting an error about unknown partition table 
for all 3 md's. md0 is boot and main programs, md1 is swap, md2 is 
mostly recordings storage for vdr. All 3 are raid 1 and raid is built in.

dmesg for .28 boot: http://pastebin.com/m1a459731
dmesg for .29 boot: http://pastebin.com/m419d7207


I tried to go directly to .32.2 but it didn't even mount md2. But that 
might have been an error by me. So was stepping through kernels to see 
where/if it stopped mounting.

The acpi error was known and seemed to effect all nforce chipset boards. 
I'm hoping that one is fixed.

^ permalink raw reply	[flat|nested] 6+ messages in thread

end of thread, other threads:[~2010-02-05  0:33 UTC | newest]

Thread overview: 6+ messages (download: mbox.gz follow: Atom feed
-- links below jump to the message on this page --
2010-01-15 23:58 unknown partition table starting with 2.6.28 Timothy D. Lenz
2010-01-16 12:43 ` John Robinson
2010-02-01 20:46   ` Bill Davidsen
2010-02-02 10:31     ` John Robinson
2010-02-05  0:25       ` Bill Davidsen
2010-02-05  0:33         ` Bill Davidsen

This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox;
as well as URLs for NNTP newsgroup(s).