Re: rcu/tree: Protect rcu_rdp_is_offloaded() invocations on RT

Frederic Weisbecker
2021-09-22T11:10:18Z

On Wed, Sep 22, 2021 at 08:32:08AM +0200, Sebastian Andrzej Siewior wrote:
> On 2021-09-22 01:45:18 [+0200], Frederic Weisbecker wrote:
> >
> > Also while at it, I'm asking again: traditionally softirqs could assume that
> > manipulating a local state was safe against !irq_count() code fiddling with
> > the same state on the same CPU.
> >
> > Now with preemptible softirqs, that assumption can be broken anytime. RCU was
> > fortunate enough to have a warning for that. But who knows how many issues like
> > this are lurking?
>
> If "local state" is modified then it is safe as long as it is modified
> within a local_bh_disable() section. And we are in this section while
> invoking a forced-threaded interrupt. The special part about RCU is
> that it is used in_irq() as part of core-code.

But local_bh_disable() was deemed for protecting from interrupting softirqs,
not the other way around (softirqs being preempted by other tasks). The latter
semantic is new and nobody had that in mind until softirqs have been made
preemptible.

For example:

CPU 0
-----------------------------------------------
SOFTIRQ RANDOM TASK
------ -----------
int *X = &per_cpu(CPUX, 0) int *X = &per_cpu(CPUX, 0)
int A, B; WRITE_ONCE(*X, 0);
WRITE_ONCE(*X, 1);
A = READ_ONCE(*X);
B = READ_ONCE(*X);

We used to have the guarantee that A == B. That's not true anymore. Now
some new explicit local_bh_disable() should be carefully placed on RANDOM_TASK
where it wasn't necessary before. RCU is not that special in this regard.