From: Steven Scholz <steven.scholz@imc-berlin.de>
To: linux-rt-users@vger.kernel.org
Subject: appearance of /proc/interrupts ?
Date: Thu, 11 Jan 2007 10:51:28 +0100 [thread overview]
Message-ID: <45A608A0.1050407@imc-berlin.de> (raw)
Hi,
with Linux 2.6.17-rt3 /proc/interrupts looks as described on
http://rt.wiki.kernel.org/index.php/RT_PREEMPT_HOWTO
CPU0
0: 11188 XT-PIC [........N/ 0]-level pit
1: 8 XT-PIC [........./ 0]-level i8042
2: 0 XT-PIC [........N/ 0]-level cascade
4: 131 XT-PIC [........./ 10]-level serial
11: 10 XT-PIC [........./ 0]-level eth0
14: 4087 XT-PIC [........./ 0]-level ide0
But when using a Linux 2.6.19.1-rt15 it looks like
CPU0
0: 15499 IO-APIC-edge timer
1: 8 IO-APIC-edge i8042
4: 161 IO-APIC-edge serial
9: 0 IO-APIC-fasteoi acpi
12: 3 IO-APIC-edge i8042
14: 4082 IO-APIC-edge ide0
16: 93 IO-APIC-fasteoi eth0
which is pretty much the same as a vanilla 2.6.19.
What does it mean? Is RT PREEMPT not working correctly?
Thanks,
Steven
next reply other threads:[~2007-01-11 9:51 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2007-01-11 9:51 Steven Scholz [this message]
2007-01-11 9:50 ` appearance of /proc/interrupts ? Ingo Molnar
2007-01-11 11:04 ` Steven Scholz
2007-01-11 11:50 ` Robert Schwebel
2007-01-11 15:19 ` Steven Scholz
2007-01-12 9:13 ` Luotao Fu
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