* [RT] remove_waiter does not need to do chain walk?(2.6.25.4-rt)
@ 2008-06-24 8:07 hyl
2008-06-26 13:13 ` hyl
0 siblings, 1 reply; 2+ messages in thread
From: hyl @ 2008-06-24 8:07 UTC (permalink / raw)
To: linux-kernel, linux-rt-users; +Cc: mingo
Hi, everyone
lets us just focus on remove_waiter in rt_spin_lock_slowlock
(2.6.25.4-rt). refer to bellowing brief code .
i notice the comments above calling the remove_waiter , but i can't
figure out the sequence which meet
the comment.
I do figure out a event sequence to proof we must call
remove_waiter , but chain walk seems is not needed.
0). current process block on this lock (note:block on lock not the process)
1). adaptive_wait continue the loop without sleeping due to event
2): owner change( held no lock while adaptive wait)
2.) owner free the lock, another process be selected as pending
owner, then release lock
2.x) then current be boosted , and become pending owner's top
waiter, so pending owner be boosted too
3. in the new round loop: do_try_to_take_rt_mutex->try_to_steal_lock
lucky own the lock,
and at this time, waiter.task is not NULL
Question is: seems pending owner's block_on is null, remove_waiter
seems need no chain walk?
My scenario may not be the one of author, please don't hesitate to
offer a example to clarity this question,
i think discuss about this make it clear and easy to maintain.
rt_spin_lock_slowlock(struct rt_mutex *lock)
{
.........
for (;;) {
if (do_try_to_take_rt_mutex(lock, STEAL_LATERAL)) {
...
if (!waiter.task) {
. ..
}
....
if (adaptive_wait(&waiter, orig_owner)) {
......
}
.....
}
....
/*
* Extremely rare case, if we got woken up by a non-mutex wakeup,
* and we managed to steal the lock despite us not being the
* highest-prio waiter (due to SCHED_OTHER changing prio), then we
* can end up with a non-NULL waiter.task:
*/
if (unlikely(waiter.task))
remove_waiter(lock, &waiter, flags);
.....
}
Regards
hyl
^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: [RT] remove_waiter does not need to do chain walk?(2.6.25.4-rt)
2008-06-24 8:07 [RT] remove_waiter does not need to do chain walk?(2.6.25.4-rt) hyl
@ 2008-06-26 13:13 ` hyl
0 siblings, 0 replies; 2+ messages in thread
From: hyl @ 2008-06-26 13:13 UTC (permalink / raw)
To: linux-kernel, linux-rt-users; +Cc: mingo
2008/6/24 hyl <heyongli@gmail.com>:
> Hi, everyone
>
> lets us just focus on remove_waiter in rt_spin_lock_slowlock
> (2.6.25.4-rt). refer to bellowing brief code .
>
> i notice the comments above calling the remove_waiter , but i can't
> figure out the sequence which meet
> the comment.
>
> I do figure out a event sequence to proof we must call
> remove_waiter , but chain walk seems is not needed.
>
> 0). current process block on this lock (note:block on lock not the process)
> 1). adaptive_wait continue the loop without sleeping due to event
> 2): owner change( held no lock while adaptive wait)
> 2.) owner free the lock, another process be selected as pending
> owner, then release lock
> 2.x) then current be boosted , and become pending owner's top
> waiter, so pending owner be boosted too
> 3. in the new round loop: do_try_to_take_rt_mutex->try_to_steal_lock
> lucky own the lock,
> and at this time, waiter.task is not NULL
>
> Question is: seems pending owner's block_on is null, remove_waiter
> seems need no chain walk?
look into the for(;;){} loop there are only one break, it is that
we got the lock.
so we must be the owner, in remove_waiter,
{
int first = (waiter == rt_mutex_top_waiter(lock));
struct task_struct *owner = rt_mutex_owner(lock);
int chain_walk = 0;
spin_lock(¤t->pi_lock);
plist_del(&waiter->list_entry, &lock->wait_list);
waiter->task = NULL;
current->pi_blocked_on = NULL;
spin_unlock(¤t->pi_lock);
if (first && owner != current && !task_is_reader(owner)) {
==>/*we are the owner, so never a chain walk for
rt_spin_lock_slowlock->remove_waiter,*/
but for mutex/reader/writer senerio, the chain walk is possible.
for rt_spin_lock, it seems that we are never going to have a non-mutex wakeup.
FIX ME.
>
> My scenario may not be the one of author, please don't hesitate to
> offer a example to clarity this question,
> i think discuss about this make it clear and easy to maintain.
>
>
> rt_spin_lock_slowlock(struct rt_mutex *lock)
> {
> .........
> for (;;) {
> if (do_try_to_take_rt_mutex(lock, STEAL_LATERAL)) {
> ...
> if (!waiter.task) {
> . ..
> }
> ....
> if (adaptive_wait(&waiter, orig_owner)) {
> ......
> }
>
> .....
> }
> ....
> /*
> * Extremely rare case, if we got woken up by a non-mutex wakeup,
> * and we managed to steal the lock despite us not being the
> * highest-prio waiter (due to SCHED_OTHER changing prio), then we
> * can end up with a non-NULL waiter.task:
> */
> if (unlikely(waiter.task))
> remove_waiter(lock, &waiter, flags);
> .....
> }
>
> Regards
> hyl
>
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2008-06-24 8:07 [RT] remove_waiter does not need to do chain walk?(2.6.25.4-rt) hyl
2008-06-26 13:13 ` hyl
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