Re: [PATCH net 5/5] net/smc: put sk reference if close work was canceled

Wenjia Zhang
2023-10-23T10:28:31Z

On 23.10.23 10:52, D. Wythe wrote:
>
>
> On 10/23/23 4:19 PM, Wenjia Zhang wrote:
>>
>>
>> On 20.10.23 04:41, D. Wythe wrote:
>>>
>>>
>>> On 10/20/23 1:40 AM, Wenjia Zhang wrote:
>>>>
>>>>
>>>> On 19.10.23 09:33, D. Wythe wrote:
>>>>>
>>>>>
>>>>> On 10/19/23 4:26 AM, Wenjia Zhang wrote:
>>>>>>
>>>>>>
>>>>>> On 17.10.23 04:06, D. Wythe wrote:
>>>>>>>
>>>>>>>
>>>>>>> On 10/13/23 3:04 AM, Wenjia Zhang wrote:
>>>>>>>>
>>>>>>>>
>>>>>>>> On 11.10.23 09:33, D. Wythe wrote:
>>>>>>>>> From: "D. Wythe" <alibuda@linux.alibaba.com>
>>>>>>>>>
>>>>>>>>> Note that we always hold a reference to sock when attempting
>>>>>>>>> to submit close_work.
>>>>>>>> yes
>>>>>>>> Therefore, if we have successfully
>>>>>>>>> canceled close_work from pending, we MUST release that reference
>>>>>>>>> to avoid potential leaks.
>>>>>>>>>
>>>>>>>> Isn't the corresponding reference already released inside the
>>>>>>>> smc_close_passive_work()?
>>>>>>>>
>>>>>>>
>>>>>>> Hi Wenjia,
>>>>>>>
>>>>>>> If we successfully cancel the close work from the pending state,
>>>>>>> it means that smc_close_passive_work() has never been executed.
>>>>>>>
>>>>>>> You can find more details here.
>>>>>>>
>>>>>>> /**
>>>>>>> * cancel_work_sync - cancel a work and wait for it to finish
>>>>>>> * @work:the work to cancel
>>>>>>> *
>>>>>>> * Cancel @work and wait for its execution to finish. This function
>>>>>>> * can be used even if the work re-queues itself or migrates to
>>>>>>> * another workqueue. On return from this function, @work is
>>>>>>> * guaranteed to be not pending or executing on any CPU.
>>>>>>> *
>>>>>>> * cancel_work_sync(&delayed_work->work) must not be used for
>>>>>>> * delayed_work's. Use cancel_delayed_work_sync() instead.
>>>>>>> *
>>>>>>> * The caller must ensure that the workqueue on which @work was last
>>>>>>> * queued can't be destroyed before this function returns.
>>>>>>> *
>>>>>>> * Return:
>>>>>>> * %true if @work was pending, %false otherwise.
>>>>>>> */
>>>>>>> boolcancel_work_sync(structwork_struct *work)
>>>>>>> {
>>>>>>> return__cancel_work_timer(work, false);
>>>>>>> }
>>>>>>>
>>>>>>> Best wishes,
>>>>>>> D. Wythe
>>>>>> As I understand, queue_work() would wake up the work if the work
>>>>>> is not already on the queue. And the sock_hold() is just prio to
>>>>>> the queue_work(). That means, cancel_work_sync() would cancel the
>>>>>> work either before its execution or after. If your fix refers to
>>>>>> the former case, at this moment, I don't think the reference can
>>>>>> be hold, thus it is unnecessary to put it.
>>>>>>>
>>>>>
>>>>> I am quite confuse about why you think when we cancel the work
>>>>> before its execution,
>>>>> the reference can not be hold ?
>>>>>
>>>>>
>>>>> Perhaps the following diagram can describe the problem in better way :
>>>>>
>>>>> smc_close_cancel_work
>>>>> smc_cdc_msg_recv_action
>>>>>
>>>>>
>>>>> sock_hold
>>>>> queue_work
>>>>> if (cancel_work_sync())        // successfully cancel before execution
>>>>> sock_put()                        //  need to put it since we
>>>>> already hold a ref before   queue_work()
>>>>>
>>>>>
>>>> ha, I already thought you might ask such question:P
>>>>
>>>> I think here two Problems need to be clarified:
>>>>
>>>> 1) Do you think the bh_lock_sock/bh_unlock_sock in the
>>>> smc_cdc_msg_recv does not protect the smc_cdc_msg_recv_action() from
>>>> cancel_work_sync()?
>>>> Maybe that would go back to the discussion in the other patch on the
>>>> behaviors of the locks.
>>>>
>>>
>>> Yes. bh_lock_sock/bh_unlock_sock can not block code execution
>>> protected by lock_sock/unlock(). That is to say, they are not exclusive.
>>>
>> No, the logic of the inference is very vague to me. My understand is
>> completely different. That is what I read from the kernel code. They
>> are not *completely* exclusive, because while the bottom half context
>> holds the lock i.e. bh_lock_sock, the process context can not get the
>> lock by lock_sock. (This is actually my main point of my argument for
>> these fixes, and I didn't see any clarify from you). However, while
>> the process context holds the lock by lock_sock, the bottom half
>> context can still get it by bh_lock_sock, this is just like what you
>> showed in the code in lock_sock. Once it gets the ownership, it
>> release the spinlock.
>>
>
> “ while the process context holds the lock by lock_sock, the bottom half
> context can still get it by bh_lock_sock,  ”
>
> You already got that, so why that sock_set_flag(DONE) and
> sock_set_flag(DEAD) can not happen concurrently ?
>

Then I'd ask how do you understand this sentence I wrote? "while the
bottom half context holds the lock i.e. bh_lock_sock, the process
context can not get the lock by lock_sock."
>
>>> We can use a very simple example to infer that since bh_lock_sock is
>>> type of spin-lock, if bh_lock_sock/bh_unlock_sock can block
>>> lock_sock/unlock(),
>>> then lock_sock/unlock() can also block bh_lock_sock/bh_unlock_sock.
>>>
>>> If this is true, when the process context already lock_sock(), the
>>> interrupt context must wait for the process to call
>>> release_sock(). Obviously, this is very unreasonable.
>>>
>>>
>>>> 2) If the queue_work returns true, as I said in the last main, the
>>>> work should be (being) executed. How could the cancel_work_sync()
>>>> cancel the work before execution successgully?
>>>
>>> No, that's not true. In fact, if queue_work returns true, it simply
>>> means that we have added the task to the queue and may schedule a
>>> worker to execute it,
>>> but it does not guarantee that the task will be executed or is being
>>> executed when it returns true,
>>> the task might still in the list and waiting some worker to execute it.
>>>
>>> We can make a simple inference,
>>>
>>> 1. A known fact is that if no special flag (WORK_UNBOUND) is given,
>>> tasks submitted will eventually be executed on the CPU where they
>>> were submitted.
>>>
>>> 2. If the queue_work returns true, the work should be or is being
>>> executed
>>>
>>> If all of the above are true, when we invoke queue_work in an
>>> interrupt context, does it mean that the submitted task will be
>>> executed in the interrupt context?
>>>
>>>
>>> Best wishes,
>>> D. Wythe
>>>
>> If you say the thread is not gauranteed to be waken up in then
>> queue_work to execute the work, please explain what the kick_pool
>> function does.
>
> I never said that.
>
What do you understand on the kick_pool there?
>>
>> However, the spin_lock understanding is still the key problem in the
>> cases. As I said, if it is not get clarify, we don't really need to go
>> on to disucss this.
>>
>>>>
>>>>>>>>> Fixes: 42bfba9eaa33 ("net/smc: immediate termination for SMCD
>>>>>>>>> link groups")
>>>>>>>>> Signed-off-by: D. Wythe <alibuda@linux.alibaba.com>
>>>>>>>>> ---
>>>>>>>>>   net/smc/smc_close.c | 3 ++-
>>>>>>>>>   1 file changed, 2 insertions(+), 1 deletion(-)
>>>>>>>>>
>>>>>>>>> diff --git a/net/smc/smc_close.c b/net/smc/smc_close.c
>>>>>>>>> index 449ef45..10219f5 100644
>>>>>>>>> --- a/net/smc/smc_close.c
>>>>>>>>> +++ b/net/smc/smc_close.c
>>>>>>>>> @@ -116,7 +116,8 @@ static void smc_close_cancel_work(struct
>>>>>>>>> smc_sock *smc)
>>>>>>>>>       struct sock *sk = &smc->sk;
>>>>>>>>>         release_sock(sk);
>>>>>>>>> -    cancel_work_sync(&smc->conn.close_work);
>>>>>>>>> +    if (cancel_work_sync(&smc->conn.close_work))
>>>>>>>>> +        sock_put(sk);
>>>>>>>>> cancel_delayed_work_sync(&smc->conn.tx_work);
>>>>>>>>>       lock_sock(sk);
>>>>>>>>>   }
>>>>>>>
>>>>>
>>>>>
>>>
>