From mboxrd@z Thu Jan 1 00:00:00 1970 From: James Bottomley Subject: Re: SCSI vs MN10300: Can get_user() be given an array? Date: Fri, 28 Jun 2013 11:16:59 -0700 Message-ID: <1372443419.1884.12.camel@dabdike> References: <5885.1372437573@warthog.procyon.org.uk> Mime-Version: 1.0 Content-Type: text/plain; charset="ISO-8859-15" Content-Transfer-Encoding: 7bit Return-path: In-Reply-To: <5885.1372437573@warthog.procyon.org.uk> Sender: linux-arch-owner@vger.kernel.org To: David Howells Cc: linux-arch@vger.kernel.org, linux-scsi@vger.kernel.org, Akira Takeuchi List-Id: linux-scsi@vger.kernel.org On Fri, 2013-06-28 at 17:39 +0100, David Howells wrote: > The MN10300 arch is throwing up an error in the SCSI driver and I'm not sure > whether it needs fixing in the arch - in get_user() - or in the SCSI code. > > The problem is this line in sg_scsi_ioctl(): > > if (get_user(opcode, sic->data)) > > sic points to the following struct: > > typedef struct scsi_ioctl_command { > unsigned int inlen; > unsigned int outlen; > unsigned char data[0]; > } Scsi_Ioctl_Command; > > However, __get_user_check() on MN10300 does this: > > const __typeof__(ptr) __guc_ptr = (ptr); > > which fails with: > > block/scsi_ioctl.c:450: error: invalid initializer > > The question is what is SCSI actually asking get_user() to do? As far as I > can tell, gcc thinks that it's being askied to declare some sort of array > here. I'm surprised you need to ask this. by convention, an array of char is usable as a pointer to char *. The compiler therefore thinks this is a legitimate conversion which doesn't need a cast: unsigned char *d = sic->data; Therefore, sic->data should be usable as a char * pointer everywhere. > Should the SCSI driver be changed to: > > if (get_user(opcode, (unsigned char *)sic->data)) can we visit reality for a minute? That proposal would require us to do an explicit (unsigned char *) conversion everywhere we use an array as a pointer value ... good grief, no! > or should the MN10300 arch be changed to morph the array into a pointer, > perhaps with: > > const __typeof__(ptr[0])* __guc_ptr = (ptr); Neither. It should do what every other architecture does, which is: const __typeof__(*(ptr)) *__guc_ptr = (ptr); James