From: Luc Van Oostenryck <luc.vanoostenryck@gmail.com>
To: Dibyendu Majumdar <mobile@majumdar.org.uk>
Cc: Linux-Sparse <linux-sparse@vger.kernel.org>
Subject: Re: Issue with bitfield
Date: Sat, 19 Aug 2017 22:18:15 +0200 [thread overview]
Message-ID: <20170819201812.7ug7bu6dwjqoetip@ltop.local> (raw)
In-Reply-To: <CACXZuxeuyK0iJp1h5J8b1BmtTroQVsbfJqkeENG3=uNyyqvDoQ@mail.gmail.com>
On Sat, Aug 19, 2017 at 02:24:59AM +0100, Dibyendu Majumdar wrote:
> Hi,
>
> This test program appears to generate incorrect IR.
>
> extern int printf(const char *s, ...);
>
> int main(void) {
> struct { char a:4; char b:4; } x = { 2, 4 };
> printf("a=%d b=%d\n", (int)x.a, (int)x.b);
> return 0;
> }
It's a very surprising bug. It's not a linearization or
an optimization bug as the AST is already wrong.
With a simpler test case, like:
struct s {
char a:4;
char b:4;
};
int foo(void)
{
struct s x = { .a = 2, .b = 4 };
return x.b;
}
you can see that the linearization produce correct
code for the initializer.
You can also see that the return statement to be
linearized is something like
STMT_RETURN
ret_value: EXPR_VALUE (value = 2)
The EXPR_VALUE means that the expression is a constant
(which is indeed the case but I would expect that the
optimization has to deduce this) but it's value is wrong
(a quick check seems to indicate that whatever selected
by the x.<member> expression, it's always the value
of the first member that we get here.
It needs real investigation, though.
It would guess for a bug in the expansion or something.
Nice catch!
-- Luc
prev parent reply other threads:[~2017-08-19 20:18 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2017-08-19 1:24 Issue with bitfield Dibyendu Majumdar
2017-08-19 20:18 ` Luc Van Oostenryck [this message]
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