[PATCH] gpu: host1x: Show all allocated syncpts via debugfs

[Jon Hunter <jonathanh@nvidia.com>]

When the host1x syncpts status is dumped via the debugfs, syncpts that
have been allocated but not yet used are not shown and so currently it
is not possible to see all the allocated syncpts. Update the path for
dumping the syncpt status via the debugfs to show all allocated syncpts
even if they have not been used yet. Note that when the syncpt status
is dumped by the kernel itself for debugging only the active syncpt are
shown.

Signed-off-by: Jon Hunter <jonathanh@nvidia.com>
---
 drivers/gpu/host1x/debug.c | 11 +++++++----
 1 file changed, 7 insertions(+), 4 deletions(-)

diff --git a/drivers/gpu/host1x/debug.c b/drivers/gpu/host1x/debug.c
index 18d9c8d206e3..34c2e36d09e9 100644
--- a/drivers/gpu/host1x/debug.c
+++ b/drivers/gpu/host1x/debug.c
@@ -75,7 +75,7 @@ static int show_channel(struct host1x_channel *ch, void *data, bool show_fifo)
 	return 0;
 }
 
-static void show_syncpts(struct host1x *m, struct output *o)
+static void show_syncpts(struct host1x *m, struct output *o, bool show_all)
 {
 	struct list_head *pos;
 	unsigned int i;
@@ -97,7 +97,10 @@ static void show_syncpts(struct host1x *m, struct output *o)
 			waiters++;
 		spin_unlock(&m->syncpt[i].intr.lock);
 
-		if (!min && !max && !waiters)
+		if (!kref_read(&m->syncpt[i].ref))
+			continue;
+
+		if (!show_all && !min && !max && !waiters)
 			continue;
 
 		host1x_debug_output(o,
@@ -124,7 +127,7 @@ static void show_all(struct host1x *m, struct output *o, bool show_fifo)
 	unsigned int i;
 
 	host1x_hw_show_mlocks(m, o);
-	show_syncpts(m, o);
+	show_syncpts(m, o, true);
 	host1x_debug_output(o, "---- channels ----\n");
 
 	for (i = 0; i < m->info->nb_channels; ++i) {
@@ -241,5 +244,5 @@ void host1x_debug_dump_syncpts(struct host1x *host1x)
 		.fn = write_to_printk
 	};
 
-	show_syncpts(host1x, &o);
+	show_syncpts(host1x, &o, false);
 }
-- 
2.25.1