[uml-devel] Question about the kernel thread in UML TT mode

[Alex LIU <alex.liu@st.com>]

Hi,all:

In UML,when do_fork was called,the new process P will be created in UML. Then in copy_thread_tt(in fact in start_fork_tramp)the corresponding process Q will be created in the host linux. I know the pid of the corresponding host process Q is appointed as the extern_pid of the UML process P. But then how will the 2 processes do next individually?

In UML,the function copy_thread_tt call start_fork_tramp, which cloned a thread. Once the thread was created it will run the outer_tramp function,in which cloned another thread. Once the second thread was created it will run the tramp function(fork_tramp or new_thread_proc). In fact the first thread is a temp one.it will kill itself later.Then why does UML clone 2 threads in copy_thread_tt?

In UML,when the kernel_thread was called,the UML kernel thread P will be created in copy_process. And the corresponding host thread Q will be create in copy_thread_tt. Then the host thread Q will run its SIGUSR1 signal handler new_thread_handler,which will call run_kernel_thread function and exited at last. But I think it should be the UML kernel thread P that call run_kernel_thread function, any problems? 

Thanks a lot!

Alex




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