From: Jeff Dike <jdike@addtoit.com>
To: akpm@osdl.org
Cc: linux-kernel@vger.kernel.org,
user-mode-linux-devel@lists.sourceforge.net,
Paolo 'Blaisorblade' Giarrusso <blaisorblade@yahoo.it>
Subject: [uml-devel] [PATCH 6/9] UML - UML/i386 is i386 when running on x86_64
Date: Mon, 29 Aug 2005 16:07:10 -0400 [thread overview]
Message-ID: <200508292007.j7TK7Ags029938@ccure.user-mode-linux.org> (raw)
From Paolo Giarrusso - Make a UML/i386 instance running on x86_64 pretend
to be i386 rather than x86_64.
Signed-off-by: Jeff Dike <jdike@addtoit.com>
Index: linux-2.6.12-rc6/arch/um/kernel/user_util.c
===================================================================
--- linux-2.6.12-rc6.orig/arch/um/kernel/user_util.c 2005-08-08 12:32:06.000000000 -0400
+++ linux-2.6.12-rc6/arch/um/kernel/user_util.c 2005-08-12 14:00:34.000000000 -0400
@@ -132,7 +132,12 @@
struct utsname host;
uname(&host);
- strcpy(machine_out, host.machine);
+ /* XXX: crude detection of 32-bit binary. */
+ if (sizeof(long) == 4 && !strcmp(host.machine, "x86_64")) {
+ strcpy(machine_out, "i686");
+ } else {
+ strcpy(machine_out, host.machine);
+ }
}
char host_info[(_UTSNAME_LENGTH + 1) * 4 + _UTSNAME_NODENAME_LENGTH + 1];
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reply other threads:[~2005-08-29 20:13 UTC|newest]
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