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From: Johannes Berg <johannes@sipsolutions.net>
To: Adrian Chadd <adrian@freebsd.org>
Cc: "linux-wireless@vger.kernel.org" <linux-wireless@vger.kernel.org>
Subject: Re: iwlegacy (4965) - what would 0x8000 as the completed TX rate indicate?
Date: Tue, 29 Oct 2013 09:03:43 +0100	[thread overview]
Message-ID: <1383033823.14377.1.camel@jlt4.sipsolutions.net> (raw)
In-Reply-To: <CAJ-Vmomsv52xc6-rwaBy9aZUsN3BaPeRTDBu8+bn2ov_Asb=1A@mail.gmail.com> (sfid-20131028_202445_048613_6F806293)

On Mon, 2013-10-28 at 12:24 -0700, Adrian Chadd wrote:

> >> So, any ideas what that 0x8000 rate in the rate completion means?
> >
> > I think that just means it used the other antenna and rate 0, since the
> > bits 0x1c000 contain the antenna bitmap that was used (up to three can
> > be used for each transmission)
> 
> Well, what's rate=0 mean?
> 
> And 0x8000 is bit 11 set, which is HT40. I definitely don't have HT40 enabled.

0x8000 is bit 15 set, which means "antenna B", I think?

But then I can't seem to figure out what rate=0 means either. Should be
an OFDM rate (bit 9 not set) but 0 isn't a valid OFDM rate value. Hmm.

johannes


  reply	other threads:[~2013-10-29  8:03 UTC|newest]

Thread overview: 6+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2013-10-26 23:56 iwlegacy (4965) - what would 0x8000 as the completed TX rate indicate? Adrian Chadd
2013-10-28 14:02 ` Johannes Berg
2013-10-28 19:24   ` Adrian Chadd
2013-10-29  8:03     ` Johannes Berg [this message]
2013-10-30  3:59       ` Adrian Chadd
2013-10-30  8:04         ` Johannes Berg

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