From: Dave Chinner <david@fromorbit.com>
To: aurfalien <aurfalien@gmail.com>
Cc: Stan Hoeppner <stan@hardwarefreak.com>, xfs@oss.sgi.com
Subject: Re: swidth in RAID
Date: Mon, 1 Jul 2013 12:09:39 +1000 [thread overview]
Message-ID: <20130701020939.GF27780@dastard> (raw)
In-Reply-To: <0DD94D98-18AA-441B-8F41-AD3AC1BCEC60@gmail.com>
On Sun, Jun 30, 2013 at 06:54:31PM -0700, aurfalien wrote:
>
> On Jun 30, 2013, at 6:38 PM, Dave Chinner wrote:
>
> > On Sun, Jun 30, 2013 at 04:42:06PM -0500, Stan Hoeppner wrote:
> >> On 6/30/2013 1:43 PM, aurfalien wrote:
> >>
> >>> I understand swidth should = #data disks.
> >>
> >> No. "swidth" is a byte value specifying the number of 512 byte blocks
> >> in the data stripe.
> >>
> >> "sw" is #data disks.
> >>
> >>> And the docs say for RAID 6 of 8 disks, that means 6.
> >>>
> >>> But parity is distributed and you actually have 8 disks/spindles working for you and a bit of parity on each.
> >>>
> >>> So shouldn't swidth equal disks in raid when its concerning distributed parity raid?
> >>
> >> No. Lets try visual aids.
> >>
> >> Set 8 coffee cups (disk drives) on a table. Grab a bag of m&m's.
> >> Separate 24 blues (data) and 8 reds (parity).
> >>
> >> Drop a blue m&m in cups 1-6 and a red into 7-8. You just wrote one RAID
> >> stripe. Now drop a blue into cups 3-8 and a red in 1-2. Your second
> >> write, this time rotating two cups (drives) to the right. Now drop
> >> blues into 5-2 and reds into 3-4. You've written your third stripe,
> >> rotating by two cups (disks) again.
> >>
> >> This is pretty much how RAID6 works. Each time we wrote we dropped 8
> >> m&m's into 8 cups, 6 blue (data chunks) and 2 red (parity chunks).
> >> Every RAID stripe you write will be constructed of 6 blues and 2 reds.
> >
> > Right, that's how they are constructed, but not all RAID distributes
> > parity across different disks in the array. Some are symmetric, some
> > are asymmetric, some rotate right, some rotate left, and some use
> > statistical algorithms to give an overall distribution without being
> > able to predict where a specific parity block might lie within a
> > stripe...
> >
> > And at the other end of the scale, isochronous RAID arrays tend to
> > have dedicated parity disks so that data read and write behaviour is
> > deterministic and therefore predictable from a high level....
> >
> > So, assuming that a RAID5/6 device has a specific data layout (be it
> > distributed or fixed) at the filesystem level is just a bad idea. We
> > simply don't know. Even if we did, the only thing we can optimise is
> > the thing that is common between all RAID5/6 devices - writing full
> > stripe widths is the most optimal method of writing to them....
>
> Am I interpreting this to say;
>
> 16 disks is sw=16 regardless of parity?
No. I'm just saying that parity layout is irrelevant to the
filesystem and that all we care about is sw does not include parity
disks.
Cheers,
Dave.
--
Dave Chinner
david@fromorbit.com
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next prev parent reply other threads:[~2013-07-01 2:09 UTC|newest]
Thread overview: 11+ messages / expand[flat|nested] mbox.gz Atom feed top
2013-06-30 18:43 swidth in RAID aurfalien
2013-06-30 19:08 ` Peter Grandi
2013-06-30 21:42 ` Stan Hoeppner
2013-06-30 22:36 ` aurfalien
2013-07-01 1:38 ` Dave Chinner
2013-07-01 1:54 ` aurfalien
2013-07-01 2:09 ` Dave Chinner [this message]
2013-07-01 2:47 ` Stan Hoeppner
2013-07-01 2:54 ` aurfalien
2013-07-02 21:48 ` Peter Grandi
2013-07-03 0:15 ` Stan Hoeppner
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