From mboxrd@z Thu Jan 1 00:00:00 1970 Message-ID: <393E4156.E7E8153A@eng.uct.ac.za> Date: Wed, 07 Jun 2000 14:34:30 +0200 From: Grant Carter MIME-Version: 1.0 To: linuxppc-embedded Subject: SMC2 Content-Type: text/plain; charset=us-ascii Sender: owner-linuxppc-embedded@lists.linuxppc.org List-Id: Hi I have been looking at uart.c in the kernel and have come across something that I cannot figure out. Perhaps I am just being stupid. Perhaps someone can set me straight please. The following code is taken fron uart.c and is used to set up either both SMC2 and SMC1 pins or, in the #else, just set up SMC1's pins. #if USE_SMC2 cp->cp_pbpar |= 0x00000cc0; cp->cp_pbdir &= ~0x00000cc0; cp->cp_pbodr &= ~0x00000cc0; #else /* This will only enable SMC1 if you want SMC2 for something else. */ cp->cp_pbpar |= 0x000000c0; cp->cp_pbdir &= ~0x000000c0; cp->cp_pbodr &= ~0x000000c0; #endif When I look at my manuals, I see no reference made to the bits 20 and 21 in pbpar, pbdir or pbodr. How does setting those bits enable the SMC2 pins? Those are located in Port A (PA8 and PA9) I guess my point is why are the Port B registers being modified for SMC2 pins which are found in Port A? Many thanks Grant -- Grant Carter gcarter@eng.uct.ac.za Department of Electrical Engineering University of Cape Town Tel: +27 (0)21 650-3467 Fax: +27 (0)21 650-3465 "Coffee not found - operator halted!" ** Sent via the linuxppc-embedded mail list. See http://lists.linuxppc.org/