linuxppc-dev.lists.ozlabs.org archive mirror
 help / color / mirror / Atom feed
* gdb load address and KERNELLOAD
@ 2001-04-04  0:57 Wang Yong
  2001-04-04  2:05 ` Dan Malek
  0 siblings, 1 reply; 11+ messages in thread
From: Wang Yong @ 2001-04-04  0:57 UTC (permalink / raw)
  To: linuxppc-embedded


Hi, all:
  I am debugging embedded Linux( linux-2.2.13 for MPC8XX) using bdm/wiggler. I do this
on windowsNT with cygwin and insight downloaded from www.ocdemon.com. The question is: how
can I download the vmlinux to a different address from KERNELLOAD which is set to 0xc0000000.
I want to do this because the SDRAM is mapped to 0x00000000 and the MMU is of course not enabled
when I download the kernel image via gdb. any comment on this subject is welcome.

  thank you.

W.Y.

** Sent via the linuxppc-embedded mail list. See http://lists.linuxppc.org/

^ permalink raw reply	[flat|nested] 11+ messages in thread
* RE: how to get the physival address
@ 2001-04-05 16:58 Hua Ji
  0 siblings, 0 replies; 11+ messages in thread
From: Hua Ji @ 2001-04-05 16:58 UTC (permalink / raw)
  To: jerry, Dan Malek; +Cc: linuxppc-embedded


>Yes, if I use kmalloc is OK, either __pa or virt_to_phys will return the
>physical address.
>But it does not work  for  defined variable (it was defined in driver so it
>should be in kernel space, isn't it?). I  wonder  which memory space, this
>variable belong to?

My 2 cents:

Given that ONLY 2 alternatives you can use for memory allocation when
working with kernel, which
are kmalloc and vmalloc, you are facing different memory usages:

Before talking further, you may have realized:

>From 0xC0000000 to 0XC0000000 + physical_memory_size is 1:1 mapped to
0x000000~physical memory size-1.

Surely, kernel also manages virtual memory from  0XC0000000 +
physical_memory_size + 8M hole to 4G

Therefore, if you used kmalloc to allocate memory, surely, you will easily
find: virtual address-3G is the physical address. However, for vmalloc, the
case is otherwise. The reason now is clear: That virtual address is very
probably from  0XC0000000 + physical_memory_size + 8M hole to 4G. This is
REALLY dynamic. Kernel's vmalloc, just like libc malloc, will go through the
free_area to find a first-bit(libc malloc is not first fit) block for you.

Anyway, back to your question. Your variable is in a memory space after 3G.
But it is byond the 3G+physical_memory_size + 8M. For example, your machine
have a 256M memory, so your variable virtual address is possible:
3G+256M+8M+SOME_VALUE.

Wish helpful,

Mike


** Sent via the linuxppc-embedded mail list. See http://lists.linuxppc.org/

^ permalink raw reply	[flat|nested] 11+ messages in thread

end of thread, other threads:[~2001-04-05 16:58 UTC | newest]

Thread overview: 11+ messages (download: mbox.gz follow: Atom feed
-- links below jump to the message on this page --
2001-04-04  0:57 gdb load address and KERNELLOAD Wang Yong
2001-04-04  2:05 ` Dan Malek
2001-04-04  6:42   ` Wolfgang Denk
2001-04-04 15:30     ` Dan Malek
2001-04-04 15:54       ` Wolfgang Denk
2001-04-05  4:13         ` how to get the physival address jerry
2001-04-05  5:58           ` Dan Malek
2001-04-05  6:28             ` jerry
2001-04-05  6:30               ` Dan Malek
2001-04-05  9:16             ` Gabriel Paubert
  -- strict thread matches above, loose matches on Subject: below --
2001-04-05 16:58 Hua Ji

This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox;
as well as URLs for NNTP newsgroup(s).