From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: from py-out-1112.google.com (py-out-1112.google.com [64.233.166.183]) by ozlabs.org (Postfix) with ESMTP id 75644DDE9A for ; Mon, 28 Jan 2008 04:20:01 +1100 (EST) Received: by py-out-1112.google.com with SMTP id z59so1818333pyg.27 for ; Sun, 27 Jan 2008 09:20:00 -0800 (PST) Message-ID: <479CAF56.30306@gmail.com> Date: Sun, 27 Jan 2008 14:20:38 -0200 From: Ricardo Severo MIME-Version: 1.0 To: linuxppc-embedded@ozlabs.org Subject: Linux boot on a ppc 405 Content-Type: text/plain; charset=ISO-8859-1; format=flowed List-Id: Linux on Embedded PowerPC Developers Mail List List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Hi all, I am working with a Xilinx Virtex II Pro evaluation board, wich has two PowerPC 405 and I'm trying to boot a vanilla linux kernel 2.6.23.14. Until now I've manged to make it uncompress the kernel, but it doesn't boot. My question is how the initial execution (the one who uncompresses the kernel image) transfers the processor to the kernel itself. I've looked in the arch/ppc/boot/simple/relocate.S code and it jumps to the position 0x0 after uncompressing, is it right? The kernel is uncompressed at that position? Thanks, -- Ricardo Ayres Severo