Re: [PATCH 00/14] replace call_rcu by kfree_rcu for simple kmem_cache_free callback

[Uladzislau Rezki <urezki@gmail.com>]

On Mon, Jun 17, 2024 at 06:57:45PM +0200, Jason A. Donenfeld wrote:
> On Mon, Jun 17, 2024 at 06:42:23PM +0200, Uladzislau Rezki wrote:
> > On Mon, Jun 17, 2024 at 06:33:23PM +0200, Jason A. Donenfeld wrote:
> > > On Mon, Jun 17, 2024 at 6:30 PM Uladzislau Rezki <urezki@gmail.com> wrote:
> > > > Here if an "err" is less then "0" means there are still objects
> > > > whereas "is_destroyed" is set to "true" which is not correlated
> > > > with a comment:
> > > >
> > > > "Destruction happens when no objects"
> > > 
> > > The comment is just poorly written. But the logic of the code is right.
> > > 
> > OK.
> > 
> > > >
> > > > >  out_unlock:
> > > > >       mutex_unlock(&slab_mutex);
> > > > >       cpus_read_unlock();
> > > > > diff --git a/mm/slub.c b/mm/slub.c
> > > > > index 1373ac365a46..7db8fe90a323 100644
> > > > > --- a/mm/slub.c
> > > > > +++ b/mm/slub.c
> > > > > @@ -4510,6 +4510,8 @@ void kmem_cache_free(struct kmem_cache *s, void *x)
> > > > >               return;
> > > > >       trace_kmem_cache_free(_RET_IP_, x, s);
> > > > >       slab_free(s, virt_to_slab(x), x, _RET_IP_);
> > > > > +     if (s->is_destroyed)
> > > > > +             kmem_cache_destroy(s);
> > >
> > Here i am not follow you. How do you see that a cache has been fully
> > freed? Or is it just super draft code?
> 
> kmem_cache_destroy() does this in shutdown_cache().
>
Right. In this scenario you invoke kmem_cache_destroy() over and over
until the last object gets freed. This potentially slowing the kmem_cache_free()
which is not OK, at least to me.

--
Uladzislau Rezki