Re: [RFC][PATCH] Make cryptoapi non-optional?

Chris Friesen
2003-08-14T20:07:36Z

David Wagner wrote:

> I don't see where you are getting this from. Define
> F(x) = first80bits(SHA(x))
> G(x) = first80bits(SHA(x)) xor last80bits(SHA(x)).
> What makes you think that F is a better (or worse) hash function than G?
>
> I think there is little basis for discriminating between them.
> If SHA is cryptographically secure, both F and G are fine.

In this case we can save the bother of doing the xor, no?

Chris

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