From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (majordomo@vger.kernel.org) by vger.kernel.org via listexpand id S268899AbUHUI0o (ORCPT ); Sat, 21 Aug 2004 04:26:44 -0400 Received: (majordomo@vger.kernel.org) by vger.kernel.org id S268898AbUHUI0o (ORCPT ); Sat, 21 Aug 2004 04:26:44 -0400 Received: from mustang.oldcity.dca.net ([216.158.38.3]:57577 "HELO mustang.oldcity.dca.net") by vger.kernel.org with SMTP id S268899AbUHUI00 (ORCPT ); Sat, 21 Aug 2004 04:26:26 -0400 Subject: RE: Entirely ignoring TCP and UDP checksum in kernel level From: Lee Revell To: Josan Kadett Cc: "'Denis Vlasenko'" , linux-kernel In-Reply-To: References: Content-Type: text/plain Message-Id: <1093076785.854.54.camel@krustophenia.net> Mime-Version: 1.0 X-Mailer: Ximian Evolution 1.4.6 Date: Sat, 21 Aug 2004 04:26:25 -0400 Content-Transfer-Encoding: 7bit Sender: linux-kernel-owner@vger.kernel.org X-Mailing-List: linux-kernel@vger.kernel.org On Sat, 2004-08-21 at 05:18, Josan Kadett wrote: > That is not much of an intelligible idea. A way to hack the kernel could be > found as I still presume. "Turn off checksums" but not by re-writing the > whole tcp code in the kernel. Isn't that possible ? Linux is an operating > system of infinite possibilities, right ? But only if you know how to hack > it... > Can't you just go into the networking code, and find the part where it checks the checksum, and just have it return success, even if the checksum was bad? Seems like a quick copy and paste hack. Am I missing something? Lee