Re: workqueue is not working?

[Misbah khan <misbah_khan@engineer.com>]

hi ..
There is a reply to you please find it and revert me back 

-misbah

Misbah khan wrote:
> 
> I didnt got very clearly what you actually did. But i guess you did faced
> some problem to work with work queue ( Bottom half of the handler ) I
> suggest you with an example code so that you could try with it and hope
> your doubt would get cleared.
> 
> /* work queue register and initialize */
> static DECLARE_WORK(queue_name,(void *)func_name,func_arq_ptr);
> 
> eg :-
> 
> static DECLARE_WORK(my_queue,(void *)my_func,NULL);
> 
> /* In the Interrupt handler you need to call the bottom half of the
> function */
> 
> schedule_work(&my_queue);
> 
> /* The function defination is like this */
> void my_func(void)
> {
>        printk(" Hello from kernal land \n");
> }
> 
> I hope this example will make your code to work for you , for any
> clarification please let me know 
> 
> thanks 
> 
> 
> 
> 
> Xin Zhao wrote:
>> 
>> I tried to schedule some work in an softirq handler. The way I did is
>> as follows:
>> 
>> I use create_workqueue to initialize a workqueue "vrpciod_workqueue",
>> 
>> in the softirq, I do INIT_WORK(work, func, data), and then
>> queue_work(vrpciod_workqueue, work);
>> 
>> I think func() should be called a bit later. However, I noticed that
>> func() is never called by the workqueue. I don't know why.
>> 
>> Can soneone give me some suggestions? Many thanks!
>> 
>> Xin
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>> 
> 
> 

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