a question regarding sys_poll() on x86_64 via tha ia32 layer

[Thomas Meyer <thomas@m3y3r.de>]

Hello,

the ia32 poll system call is routed through the "standard" function
sys_poll().

This function is defined as:

SYSCALL_DEFINE3(poll, struct pollfd __user *, ufds, unsigned int, nfds,
		long, timeout_msecs)

in fs/select.c

timeout_msecs is of type long which is AFAIK is 4 bytes on x86 and 8
bytes on x86_64.

the test for sign (i.e. < 0) in the objdump is done against the 64 bit
register (here %rbx):

ffffffff811313e0 <sys_poll>:
ffffffff811313e0:       55                      push   %rbp
ffffffff811313e1:       48 89 e5                mov    %rsp,%rbp
ffffffff811313e4:       48 83 ec 30             sub    $0x30,%rsp
ffffffff811313e8:       48 89 5d e8             mov    %rbx,-0x18(%rbp)
ffffffff811313ec:       48 89 d3                mov    %rdx,%rbx
ffffffff811313ef:       31 d2                   xor    %edx,%edx
ffffffff811313f1:       48 85 db                test   %rbx,%rbx
ffffffff811313f4:       4c 89 65 f0             mov    %r12,-0x10(%rbp)
ffffffff811313f8:       4c 89 6d f8             mov    %r13,-0x8(%rbp)
ffffffff811313fc:       41 89 f4                mov    %esi,%r12d
ffffffff811313ff:       49 89 fd                mov    %rdi,%r13
ffffffff81131402:       78 42                   js     ffffffff81131446 <sys_poll+0x66>

on an x86 kernel the test is done against %ebx

so when the system call is called with %rbx = 00000000ffffffff (i.e. -1
from %ebx) on an x86_64 kernel via the ia32 layer the test for sign will
fail and the timer will be set.

btw. <sys/poll.h> seems to define the function as

extern int poll (struct pollfd *__fds, nfds_t __nfds, int __timeout);

what am I overloking?

mfg
thomas