Re: [PATCH 1/5] kfifo: remove unnecessary type check

[Stefani Seibold <stefani@seibold.net>]

Am Mittwoch, den 09.01.2013, 10:35 +0800 schrieb Yuanhan Liu:
> On Tue, Jan 08, 2013 at 10:51:04PM +0100, Stefani Seibold wrote:
> > Am Dienstag, den 08.01.2013, 22:57 +0800 schrieb Yuanhan Liu:
> > > Firstly, this kind of type check doesn't work. It does something similar
> > > as following:
> > > 	void * __dummy = NULL;
> > > 	__buf = __dummy;
> > > 
> > > __dummy is defined as void *. Thus it will not trigger warnings as
> > > expected.
> > > 
> > > Second, we don't need that kind of check. Since the prototype
> > > of __kfifo_out is:
> > > 	unsigned int __kfifo_out(struct __kfifo *fifo,  void *buf, unsigned int len)
> > > 
> > > buf is defined as void *, so we don't need do the type check. Remove it.
> > > 
> > 
> > Thats wrong.
> > 
> > First the type checking will be used in kfifo_put() and kfifo_in() for
> > const types to check if the passed type of the data can converted to the
> > fifo element type. 
> 
> Hi Stefani,
> 
> Yes, I see now. After rechecking the code, I found that this kind of
> type checking only works for those static defined kifo by
> DECLARE/DEFINE_KFIFO. As the ptrtype is the same as the data type:
> 
>     /* the 4th argument "type" is "ptrtype" */
>     #define STRUCT_KFIFO(type, size) struct __STRUCT_KFIFO(type, size, 0, type)
> 
>     #define DECLARE_KFIFO(fifo, type, size) STRUCT_KFIFO(type, size) fifo
> 
> While, for those kfifo dynamically allocated, the type checking will not
> work as expected then as ptrtype is always "void":
> 
>     struct kfifo __STRUCT_KFIFO_PTR(unsigned char, 0, void);
> 

You should avoid using struct kfifo, as you can read in kfifo.h this is
only for compatibility reason.

If you use the macro DECLARE_KFIFO_PTR(), DECLARE_KFIFO() or
DEFINE_KFIFO() instead.

Have a look at the examples files in the samples/kfifo directory.

- Stefani