Re: timing out on a semaphore

Tim Waugh
2001-02-27T23:29:25Z

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On Tue, Feb 27, 2001 at 10:40:35PM +0000, Andrew Morton wrote:

> 1: Your code is leaving the semaphore in a down'ed state
> somehow.

This was probably it. I don't know why it works for me but not some
other people though. :-/

> (As you can tell, I'm desparately avoiding having
> to understand the semaphore code again :))

:-)

Tim.
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