From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (majordomo@vger.kernel.org) by vger.kernel.org via listexpand id ; Sun, 19 Aug 2001 02:38:41 -0400 Received: (majordomo@vger.kernel.org) by vger.kernel.org id ; Sun, 19 Aug 2001 02:38:31 -0400 Received: from snark.tuxedo.org ([207.106.50.26]:60422 "EHLO snark.thyrsus.com") by vger.kernel.org with ESMTP id ; Sun, 19 Aug 2001 02:38:16 -0400 Date: Sun, 19 Aug 2001 02:42:33 -0400 From: "Eric S. Raymond" To: Linux Kernel List Cc: gars@lanm-pc.com Subject: Swap size for a machine with 2GB of memory Message-ID: <20010819024233.A26916@thyrsus.com> Reply-To: esr@thyrsus.com Mail-Followup-To: "Eric S. Raymond" , Linux Kernel List , gars@lanm-pc.com Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline User-Agent: Mutt/1.2.5i Organization: Eric Conspiracy Secret Labs X-Eric-Conspiracy: There is no conspiracy Sender: linux-kernel-owner@vger.kernel.org X-Mailing-List: linux-kernel@vger.kernel.org The Red Hat installation manual claims that the size of the swap partition should be twice the size of physical memory, but no more than 128MB. The screaming hotrod machine Gary Sandine and I built around the Tyan S2464 has 2GB of physical memory. Should I believe the above formula? If not, is there a more correct one for calculating needed swap on machines with very large memory? (No further hangs, BTW.) -- Eric S. Raymond .. a government and its agents are under no general duty to provide public services, such as police protection, to any particular individual citizen... -- Warren v. District of Columbia, 444 A.2d 1 (D.C. App.181)