Reg. asm-sparc64/processor.h

Reg. asm-sparc64/processor.h

[Shanti Katta]

Hi,
I am trying to port User-mode-linux to Sparc64 architecture. I have the
debian(sid) on my host system with custom built 2.4.18 kernel. When I
try to generate some header file for UML that #included
<asm-sparc64/processor.h> file, I was getting parse errors for u64 data
types. When I changed all those U64 data-types to __u64 type, it fixed
the error. So, I was just wondering, whether it is the right thing to
do.

-Thanks in advance
-Shanti Katta

Re: Reg. asm-sparc64/processor.h

[David S. Miller]

If you want the 'u64' type, define __KERNEL__.  That is what
every platform does, protect the types without underscores with
a __KERNEL__ ifdef.

Re: Reg. asm-sparc64/processor.h

[Shanti Katta]

On Wed, 2002-05-22 at 23:52, David S. Miller wrote:
> 
> If you want the 'u64' type, define __KERNEL__.  That is what
> every platform does, protect the types without underscores with
> a __KERNEL__ ifdef.
Hi,
In asm-sparc64/processor.h (2.4.18), in thread_struct structure, there
are 3 fields:
        u64 *user_cntd0, *user_cntd1;
        u64 kernel_cntd0, kernel_cntd1;
        u64 pcr_reg; 

which are defined without #ifdef __KERNEL__ . I guess, this is a bug,
which needs fixing.

Thanks
-Regards
-Shanti Katta

Re: Reg. asm-sparc64/processor.h

[David S. Miller]

   From: Shanti Katta <katta@csee.wvu.edu>
   Date: 23 May 2002 19:24:35 -0400

   On Wed, 2002-05-22 at 23:52, David S. Miller wrote:
   > 
   > If you want the 'u64' type, define __KERNEL__.  That is what
   > every platform does, protect the types without underscores with
   > a __KERNEL__ ifdef.

   In asm-sparc64/processor.h (2.4.18), in thread_struct structure, there
   are 3 fields:
           u64 *user_cntd0, *user_cntd1;
           u64 kernel_cntd0, kernel_cntd1;
           u64 pcr_reg; 
   
   which are defined without #ifdef __KERNEL__ . I guess, this is a bug,
   which needs fixing.

You shouldn't be including such kernel headers from userspace.