Re: [PATCH 2/6] sched: make sched_slice() group scheduling savvy

Peter Zijlstra
2007-11-01T12:20:25Z

On Thu, 2007-11-01 at 13:03 +0100, Peter Zijlstra wrote:
> On Thu, 2007-11-01 at 12:58 +0100, Peter Zijlstra wrote:
>
> > > sched_slice() is about lantecy, its intended purpose is to ensure each
> > > task is ran exactly once during sched_period() - which is
> > > sysctl_sched_latency when nr_running <= sysctl_sched_nr_latency, and
> > > otherwise linearly scales latency.
>
> The thing that got my brain in a twist is what to do about the non-leaf
> nodes, for those it seems I'm not doing the right thing - I think.

Ok, suppose a tree like so:

level 2 cfs_rq
A B

level 1 cfs_rqA cfs_rqB
A0 B0 - B99

So for sake of determinism, we want to impose a period in which all
level 1 tasks will have ran (at least) once.

Now what sched_slice() does is calculate the weighted proportion of the
given period for each task to run, so that each task runs exactly once.

Now level 2, can introduce these large weight differences, which in this
case result in 'lumps' of time.

In the given example above the weight difference is 1:100, which is
already at the edges of what regular nice levels could do.

How about limiting the max output of sched_slice() to
sysctl_sched_latency in order to break up these large stretches of time?

Index: linux-2.6/kernel/sched_fair.c
===================================================================
--- linux-2.6.orig/kernel/sched_fair.c
+++ linux-2.6/kernel/sched_fair.c
@@ -341,7 +341,7 @@ static u64 sched_slice(struct cfs_rq *cf
do_div(slice, cfs_rq->load.weight);
}

- return slice;
+ return min_t(u64, sysctl_sched_latency, slice);
}

/*