Re: Could not set non-blocking flag with 2.6.24-rc5

["Rafael J. Wysocki" <rjw@sisk.pl>]

On Thursday, 13 of December 2007, Tino Keitel wrote:
> Hi folks,
> 
> I often build Debian packages inside a chroot. Today I discovered a
> failure during an "aptitude update", which is a command to download new
> package lists for the package management. In strace, the lines around
> the failure look like this:
> 
> 99% [Working])         = 14 14
> [pid  5986] select(6, [3 4 5], [], NULL, {0, 500000}) = 0 (Timeout)
> [pid  5986] gettimeofday({1197576353, 670510}, NULL) = 0
> [pid  5986] rt_sigprocmask(SIG_BLOCK, [WINCH], [], 8) = 0
> [pid  5986] rt_sigprocmask(SIG_SETMASK, [], NULL, 8) = 0
> 99% [Working])         = 14 14
> [pid  5986] select(6, [3 4 5], [], NULL, {0, 500000}) = 0 (Timeout)
> [pid  5986] gettimeofday({1197576354, 173902}, NULL) = 0
> [pid  5986] rt_sigprocmask(SIG_BLOCK, [WINCH], [], 8) = 0
> [pid  5986] rt_sigprocmask(SIG_SETMASK, [], NULL, 8) = 0
> 99% [Working])         = 14 14
> [pid  5986] select(6, [3 4 5], [], NULL, {0, 500000} <unfinished ...>
> [pid  5988] <... select resumed> )      = 1 (in [3], left {105, 0})
> [pid  5988] read(3, "", 56559)          = 0
> [pid  5988] fcntl64(-1, F_GETFL)        = -1 EBADF (Bad file
> descriptor)
> [pid  5988] fcntl64(-1, F_SETFL,
> O_ACCMODE|O_CREAT|O_EXCL|O_NOCTTY|O_TRUNC|O_APPEND|O_SYNC|O_ASYNC|O_DIRECT|O_LARGEFILE|O_DIRECTORY|O_NOFOLLOW|O_NOATIME|0xfff8003c)
> = -1 EBADF (Bad file descriptor)
> [pid  5988] write(2, ""..., 41FATAL -> Could not set non-blocking flag
> )         = 41
> [pid  5988] write(2, ""..., 19Bad file descriptor)         = 19
> [pid  5988] write(2, ""..., 1
> )          = 1
> [pid  5988] exit_group(100)             = ?
> Process 5988 detached
> 
> This happened with a kernel after 2.6.24-rc5
> (4af75653031c6d454b4ace47c1536f0d2e727e3e). I rebooted into 2.6.23.8
> and it worked. Now I rebooted into 2.6.24-rc5 again and was able to
> reproduce the failure, so it looks like a kernel issue to me.

Yes, it does.

I'm not sure who to forward it to, though.  Andrew, can you help, please?