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From: Srivatsa Vaddagiri <vatsa@linux.vnet.ibm.com>
To: "Paul Menage" <menage@google.com>
Cc: linux-kernel@vger.kernel.org, a.p.zijlstra@chello.nl,
	"Ingo Molnar" <mingo@elte.hu>,
	containers@lists.osdl.org, dhaval@linux.vnet.ibm.com,
	"Balbir Singh" <balbir@in.ibm.com>,
	pj@sgi.com
Subject: Re: [RFC] Default child of a cgroup
Date: Fri, 1 Feb 2008 13:49:31 +0530	[thread overview]
Message-ID: <20080201081931.GA21572@linux.vnet.ibm.com> (raw)
In-Reply-To: <6599ad830801311839x33cf2ebco9f501571fc129b11@mail.gmail.com>

On Thu, Jan 31, 2008 at 06:39:56PM -0800, Paul Menage wrote:
> On Jan 30, 2008 6:40 PM, Srivatsa Vaddagiri <vatsa@linux.vnet.ibm.com> wrote:
> >
> > Here are some questions that arise in this picture:
> >
> > 1. What is the relationship of the task-group in A/tasks with the
> >    task-group in A/a1/tasks? In otherwords do they form siblings
> >    of the same parent A?
> 
> I'd argue the same as Balbir - tasks in A/tasks are are children of A
> and are siblings of a1, a2, etc.

> > 2. Somewhat related to the above question, how much resource should the
> >    task-group A/a1/tasks get in relation to A/tasks? Is it 1/2 of parent
> >    A's share or 1/(1 + N) of parent A's share (where N = number of tasks
> >    in A/tasks)?
> 
> Each process in A should have a scheduler weight that's derived from
> its static_prio field. Similarly each subgroup of A will have a
> scheduler weight that's determined by its cpu.shares value. So the cpu
> share of any child (be it a task or a subgroup) would be equal to its
> own weight divided by the sum of weights of all children.

Assuming all tasks are of same prio, then what you are saying is that
A/a1/tasks should cumulatively recv 1/(1 + N) of parent's share.

After some thought, that seems like a reasonable expectation. The only issue
I have for that is it breaks current behavior in mainline. Assume this
structure:

 	   /
 	   |------<tasks>
 	   |------<cpuacct.usage>
  	   |------<cpu.shares>
 	   |
 	   |----[A]
 	   |     |----<tasks>
 	   |     |----<cpuacct.usage>
 	   |     |----<cpu.shares>


then, going by above argument, /A/tasks should recv 1/(1+M)% of system
resources (M -> number of tasks in /tasks), whereas it receives 1/2 of
system resources currently (assuming /cpu.shares and /A/cpu.shares are
same).

Balbir, is this behaviour same for memory controller as well?

So pick any option, we are talking of deviating from current
behavior, which perhaps is a non-issue if we want to DTRT.

> So yes, if a task in A forks lots of children, those children could
> end up getting a disproportionate amount of the CPU compared to tasks
> in A/a1 - but that's the same as the situation without cgroups. If you
> want to control cpu usage between different sets of processes in A,
> they should be in sibling cgroups, not directly in A.
> 
> Is there a restriction in CFS that stops a given group from
> simultaneously holding tasks and sub-groups? If so, couldn't we change
> CFS to make it possible rather than enforcing awkward restructions on
> cgroups?

Should be possible, need to look closely at what will need to change
(load_balance routines for sure).

-- 
Regards,
vatsa

      parent reply	other threads:[~2008-02-01  8:15 UTC|newest]

Thread overview: 13+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2008-01-31  2:40 [RFC] Default child of a cgroup Srivatsa Vaddagiri
2008-01-31 17:44 ` Serge E. Hallyn
2008-01-31 18:09 ` Balbir Singh
2008-01-31 20:37   ` Peter Zijlstra
2008-02-01  4:16     ` Dhaval Giani
2008-02-01  3:53   ` Dhaval Giani
2008-01-31 21:13 ` Vivek Goyal
2008-02-01  2:39 ` Paul Menage
2008-02-01  3:32   ` Balbir Singh
2008-02-01  3:40   ` Dhaval Giani
2008-02-01  7:58   ` Peter Zijlstra
2008-02-01 15:35     ` Paul Menage
2008-02-01  8:19   ` Srivatsa Vaddagiri [this message]

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