RE: [tip:sched/urgent] sched: Print sched_group::__cpu_power in sched_domain_debug

Luck, Tony
2009-04-14T16:30:26Z

- group->__cpu_power);
+ if (group->__cpu_power != SCHED_LOAD_SCALE)
+ printk(KERN_CONT " %s (__cpu_power = %d)", str,
+ group->__cpu_power);

Much quieter ... but perhaps a little too quiet?
Is this what you want? Now the console output looks like this:

CPU0 attaching sched-domain:
domain 0: span 0-15 level CPU
groups:
CPU1 attaching sched-domain:
domain 0: span 0-15 level CPU
groups:
CPU2 attaching sched-domain:
domain 0: span 0-15 level CPU
groups:
...

instead of the original:

CPU0 attaching sched-domain:
domain 0: span 0-15 level CPU
groups: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
CPU1 attaching sched-domain:
domain 0: span 0-15 level CPU
groups: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0
CPU2 attaching sched-domain:
domain 0: span 0-15 level CPU
groups: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0 1
...

Either we don't need the empty "groups:" line, or we should
still list the cpus in the group? I'm not really sure what
information you are trying to convey here.

-Tony