[PATCH 14/16] x86/ioapic.c: clean up replace_pin_at_irq_node logic and comments

Jeremy Fitzhardinge
2009-06-16T20:18:09Z

There's no need for a control variable in replace_pin_at_irq_node();
it can just return if it finds the old apic/pin to replace.

If the loop terminates, then it didn't find the old apic/pin, so it can
add the new ones.

Signed-off-by: Jeremy Fitzhardinge <jeremy.fitzhardinge@citrix.com>
---
arch/x86/kernel/apic/io_apic.c | 13 +++++--------
1 files changed, 5 insertions(+), 8 deletions(-)

diff --git a/arch/x86/kernel/apic/io_apic.c b/arch/x86/kernel/apic/io_apic.c
index b71d2a2..f466a1e 100644
--- a/arch/x86/kernel/apic/io_apic.c
+++ b/arch/x86/kernel/apic/io_apic.c
@@ -509,25 +509,22 @@ static void add_pin_to_irq_node(struct irq_cfg *cfg, int node, int apic, int pin
* Reroute an IRQ to a different pin.
*/
static void __init replace_pin_at_irq_node(struct irq_cfg *cfg, int node,
- int oldapic, int oldpin,
- int newapic, int newpin)
+ int oldapic, int oldpin,
+ int newapic, int newpin)
{
struct irq_pin_list *entry;
- int replaced = 0;

for (entry = cfg->irq_2_pin; entry != NULL; entry = entry->next) {
if (entry->apic == oldapic && entry->pin == oldpin) {
entry->apic = newapic;
entry->pin = newpin;
- replaced = 1;
/* every one is different, right? */
- break;
+ return;
}
}

- /* why? call replace before add? */
- if (!replaced)
- add_pin_to_irq_node(cfg, node, newapic, newpin);
+ /* old apic/pin didn't exist, so just add new ones */
+ add_pin_to_irq_node(cfg, node, newapic, newpin);
}

static void io_apic_modify_irq(struct irq_cfg *cfg,
--
1.6.2.2