On Wed, Jul 01, 2009 at 01:03:55PM +0800, Zhang, Yanmin wrote: > On Wed, 2009-07-01 at 12:10 +0800, Wu Fengguang wrote: > > On Wed, Jul 01, 2009 at 11:25:33AM +0800, Zhang, Yanmin wrote: > > > Comapraing with 2.6.30, fio sync read (block size 4k) has about 35% regression > > > with kernel 2.6.31-rc1 on my stoakley machine with a JBOD (13 SCSI disks). > > > > > > Every disk has 1 partition and 4 1-GB files. Start 10 processes per disk to > > > do sync read sequentinally. > > > > > > Bisected down to below patch. > > > > > > 51daa88ebd8e0d437289f589af29d4b39379ea76 is first bad commit > > > commit 51daa88ebd8e0d437289f589af29d4b39379ea76 > > > Author: Wu Fengguang > > > Date: Tue Jun 16 15:31:24 2009 -0700 > > > > > > readahead: remove sync/async readahead call dependency > > > > > > The readahead call scheme is error-prone in that it expects the call sites > > > to check for async readahead after doing a sync one. I.e. > > > > > > if (!page) > > > page_cache_sync_readahead(); > > > page = find_get_page(); > > > if (page && PageReadahead(page)) > > > page_cache_async_readahead(); > > > > > > > > > I also test block size 64k and 128k, but they don't have regression. Perhaps > > > the default read_ahead_kb is equal to 128? > > > > > > Other 2 machines have no such regression. The JBODS of the 2 machines consists > > > of 12 and 7 SATA/SAS disks while every disk has 2 partitions. > > > > Yanmin, thanks for the tests! > > > > Maybe the patch posted here can restore the performance: > > > > http://lkml.org/lkml/2009/5/21/319 > I tried it and it doesn't help. Then let's check what's happening behind the scene :) Please apply the attached patch and run echo 1 > /debug/readahead/trace_enable # do benchmark echo 0 > /debug/readahead/trace_enable and send the dmesg which will contain lots of lines like [ 54.738105] readahead-initial0(pid=3290(zsh), dev=00:10(0:10), ino=105910(dmesg), req=0+1, ra=0+4-3, async=0) = 2 [ 54.751801] readahead-subsequent(pid=3290(dmesg), dev=00:10(0:10), ino=105910(dmesg), req=1+60, ra=4+8-8, async=1, miss=0) = 0 Thank you very much, Fengguang