[ 04/53] genirq: Avoid deadlock in spurious handling

Greg Kroah-Hartman
2013-02-27T00:35:19Z

From: Thomas Gleixner <tglx@linutronix.de>

commit e716efde75267eab919cdb2bef5b2cb77f305326 upstream.

commit 52553ddf(genirq: fix regression in irqfixup, irqpoll)
introduced a potential deadlock by calling the action handler with the
irq descriptor lock held.

Remove the call and let the handling code run even for an interrupt
where only a single action is registered. That matches the goal of
the above commit and avoids the deadlock.

Document the confusing action = desc->action reload in the handling
loop while at it.

Reported-and-tested-by: "Wang, Warner" <warner.wang@hp.com>
Tested-by: Edward Donovan <edward.donovan@numble.net>
Cc: "Wang, Song-Bo (Stoney)" <song-bo.wang@hp.com>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>

---
kernel/irq/spurious.c | 7 +++----
1 file changed, 3 insertions(+), 4 deletions(-)

--- a/kernel/irq/spurious.c
+++ b/kernel/irq/spurious.c
@@ -80,13 +80,11 @@ static int try_one_irq(int irq, struct i

/*
* All handlers must agree on IRQF_SHARED, so we test just the
- * first. Check for action->next as well.
+ * first.
*/
action = desc->action;
if (!action || !(action->flags & IRQF_SHARED) ||
- (action->flags & __IRQF_TIMER) ||
- (action->handler(irq, action->dev_id) == IRQ_HANDLED) ||
- !action->next)
+ (action->flags & __IRQF_TIMER))
goto out;

/* Already running on another processor */
@@ -104,6 +102,7 @@ static int try_one_irq(int irq, struct i
do {
if (handle_irq_event(desc) == IRQ_HANDLED)
ret = IRQ_HANDLED;
+ /* Make sure that there is still a valid action */
action = desc->action;
} while ((desc->istate & IRQS_PENDING) && action);
desc->istate &= ~IRQS_POLL_INPROGRESS;