Re: [PATCH 2/3] sched: don't call get_group() for covered cpus

[Peter Zijlstra <peterz@infradead.org>]

On Tue, Jun 11, 2013 at 04:32:44PM +0530, Viresh Kumar wrote:
> In build_sched_groups() we don't need to call get_group() for cpus which are
> already covered in previous iterations. So, call get_group() after checking if
> cpu is covered or not.
> 

Aside from not needing it; doing it would mark the group used and
eventually leak it since we wouldn't connect it and not find it again to
free it, right?

So effectively this fixes a memory leak?

> Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org>
> ---
>  kernel/sched/core.c | 4 ++--
>  1 file changed, 2 insertions(+), 2 deletions(-)
> 
> diff --git a/kernel/sched/core.c b/kernel/sched/core.c
> index 4abc743..27842f5 100644
> --- a/kernel/sched/core.c
> +++ b/kernel/sched/core.c
> @@ -5344,12 +5344,12 @@ build_sched_groups(struct sched_domain *sd, int cpu)
>  
>  	for_each_cpu(i, span) {
>  		struct sched_group *sg;
> -		int group = get_group(i, sdd, &sg);
> -		int j;
> +		int group, j;
>  
>  		if (cpumask_test_cpu(i, covered))
>  			continue;
>  
> +		group = get_group(i, sdd, &sg);
>  		cpumask_clear(sched_group_cpus(sg));
>  		sg->sgp->power = 0;
>  		cpumask_setall(sched_group_mask(sg));
> -- 
> 1.7.12.rc2.18.g61b472e
>