From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (majordomo@vger.kernel.org) by vger.kernel.org via listexpand id S1751221AbcGLNf5 (ORCPT ); Tue, 12 Jul 2016 09:35:57 -0400 Received: from mx1.redhat.com ([209.132.183.28]:50634 "EHLO mx1.redhat.com" rhost-flags-OK-OK-OK-OK) by vger.kernel.org with ESMTP id S1750947AbcGLNf4 (ORCPT ); Tue, 12 Jul 2016 09:35:56 -0400 Date: Tue, 12 Jul 2016 15:35:52 +0200 From: Jiri Olsa To: Steven Rostedt Cc: Jiri Olsa , Arnaldo Carvalho de Melo , lkml , David Ahern , Ingo Molnar , Namhyung Kim , Peter Zijlstra Subject: Re: [PATCH 10/10] perf script python: Fix string vs byte array resolving Message-ID: <20160712133552.GA30438@krava> References: <1468148882-10362-1-git-send-email-jolsa@kernel.org> <1468148882-10362-11-git-send-email-jolsa@kernel.org> <20160711115452.02ba1d6c@gandalf.local.home> <20160712081156.GB3392@krava> <20160712083728.2c468986@gandalf.local.home> <20160712125245.GA20585@krava> <20160712090001.0e8cdb6d@gandalf.local.home> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline In-Reply-To: <20160712090001.0e8cdb6d@gandalf.local.home> User-Agent: Mutt/1.6.1 (2016-04-27) X-Greylist: Sender IP whitelisted, not delayed by milter-greylist-4.5.16 (mx1.redhat.com [10.5.110.38]); Tue, 12 Jul 2016 13:35:55 +0000 (UTC) Sender: linux-kernel-owner@vger.kernel.org List-ID: X-Mailing-List: linux-kernel@vger.kernel.org On Tue, Jul 12, 2016 at 09:00:01AM -0400, Steven Rostedt wrote: > On Tue, 12 Jul 2016 14:52:45 +0200 > Jiri Olsa wrote: > > > > hum, so string is not passed to trace buffer with 0 at the end? > > strlen() returns only the length of the string (minus the \0 at the > end). yea, is_printable_array is called here on tracepoint data that's why I asked.. is 0 part of the string data when stored within tracepoint? > > > > > I'll check the option of passing everything as PyByteArray. > > If it's the same for user, we'll have simpler code in here. > > > > > > > > because the last byte wont be 0. What about: > > > > > > for (i = 0; i < len; i++) > > > if (!isprint(p[i]) && !isspace(p[i])) > > > break; > > > > > > return i == len || > > > (i == len - 1 && p[i] == 0); > > Or you can do: > > if (p[len - 1] == 0) > len--; > > for (i = 0; i < len; i++) > if (!isprint(p[i]) && !isspace(p[i])) > return 0; > return 1; yep, seems good.. thanks jirka