Re: [PATCH] printk: Do not lose last line in kmsg dump

[Sergey Senozhatsky <sergey.senozhatsky.work@gmail.com>]

On (07/09/19 10:10), Vincent Whitchurch wrote:
> A dump of a 64-byte buffer filled by kmsg_dump_get_buffer(), before this
> patch:
> 
>  00000000: 3c 30 3e 5b 20 20 20 20 36 2e 35 32 32 31 39 37  <0>[    6.522197
>  00000010: 5d 20 41 41 41 41 41 41 41 41 41 41 41 41 41 0a  ] AAAAAAAAAAAAA.
>  00000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
>  00000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
> 
> After this patch:
> 
>  00000000: 3c 30 3e 5b 20 20 20 20 36 2e 34 32 37 35 30 32  <0>[    6.427502
>  00000010: 5d 20 41 41 41 41 41 41 41 41 41 41 41 41 41 0a  ] AAAAAAAAAAAAA.
>  00000020: 3c 30 3e 5b 20 20 20 20 36 2e 34 32 37 37 36 39  <0>[    6.427769
>  00000030: 5d 20 42 42 42 42 42 42 42 42 31 32 33 34 35 0a  ] BBBBBBBB12345.

[..]

> @@ -1318,7 +1318,7 @@ static size_t msg_print_text(const struct printk_log *msg, bool syslog,
>  		}
>  
>  		if (buf) {
> -			if (prefix_len + text_len + 1 >= size - len)
> +			if (prefix_len + text_len + 1 > size - len)
>  				break;

So with this patch the last byte of the buffer is 0xA. It's a bit
uncomfortable that `len', which we return from msg_print_text(),
now points one byte beyond the buffer:

	buf[len++] = '\n';
	return len;

This is not very common. Not sure what usually happens to kmsg_dump
buffers, but anyone who'd do a rather innocent

	kmsg_dump(buf, &len);
	buf[len] = 0x00;

will write to something which is not a kmsg buffer (in some cases).

	-ss