Re: [PATCH v14 1/4] asm-generic,arm64: create task variant of access_ok

Oleg Nesterov
2023-03-29T15:16:53Z

Hmm. I am not comfortable with this change...

I won't really argue because I don't have a better solution and because
I think we don't really care as long as task_set_syscall_user_dispatch()
is the only user of task_access_ok(), but still...

OK, so this version changes set_syscall_user_dispatch() to use
task_access_ok() instead of access_ok() because task != current.

On 03/28, Gregory Price wrote:
>
> If the architecture does not implement task_access_ok, the operation
> reduces to access_ok and the task argument is discarded.

No, with this patch it reduces to __access_ok(). And this already doesn't
look very good to me, but this is minor.

> --- a/include/asm-generic/access_ok.h
> +++ b/include/asm-generic/access_ok.h
> @@ -45,4 +45,14 @@ static inline int __access_ok(const void __user *ptr, unsigned long size)
> #define access_ok(addr, size) likely(__access_ok(addr, size))
> #endif
>
> +/*
> + * Some architectures may have special features (such as ARM MTE)
> + * that require handling if access_ok is called on a pointer from one
> + * task in the context of another. On most architectures this operation
> + * is equivalent to simply __access_ok.
> + */
> +#ifndef task_access_ok
> +#define task_access_ok(task, addr, size) likely(__access_ok(addr, size))
> +#endif

Lets ignore arm64.

This look as if access_ok() or __access_ok() doesn't depend on task, but
this is not true in general. Say, TASK_SIZE_MAX can check is_32bit_task()
test_thread_flag(TIF_32BIT...) and this uses "current".

Again, we probably do not care, but I don't like the fact task_access_ok()
looks as if task_access_ok(task) returns the same result as "task" calling
access_ok().

Oleg.