From: Parav Pandit <paravpandit@yahoo.com>
To: Linux kernel <linux-kernel@vger.kernel.org>
Subject: Re: Calculating time in order of 0.1usec on x86 system
Date: Tue, 30 Sep 2008 02:37:57 -0700 (PDT) [thread overview]
Message-ID: <215667.93774.qm@web30102.mail.mud.yahoo.com> (raw)
In-Reply-To: <855204.33912.qm@web30108.mail.mud.yahoo.com>
I am getting my desired numbers.
get_cycles()/cpu_khz gives the right time interval on x86 system.
Parav
--- On Tue, 9/30/08, Parav Pandit <paravpandit@yahoo.com> wrote:
> From: Parav Pandit <paravpandit@yahoo.com>
> Subject: Calculating time in order of 0.1usec on x86 system
> To: "Linux kernel" <linux-kernel@vger.kernel.org>
> Date: Tuesday, September 30, 2008, 12:31 PM
> Hi,
>
> I need to calculate time spent by a function in order of
> less then a microsecond on x86 SMP platform.
>
> Current profiling tools and gettimeofday() are not
> sufficient.
>
> So I am using get_cycles() to get the CPU cycles.
>
> Now how do I convert it into the time interval?
>
> Do I have to divide it by "cpu_khz" variable? Or
> some other method?
> Is yes, what will be the unit of the result (time
> interval)? nsec/usec/msec?
>
> e.g. get_cycles()/cpu_khz (unit?)
>
> Or Is there more simpler method exist?
>
> Regards,
> Parav Pandit
>
>
>
> --
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prev parent reply other threads:[~2008-09-30 9:38 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2008-09-30 7:01 Calculating time in order of 0.1usec on x86 system Parav Pandit
2008-09-30 9:37 ` Parav Pandit [this message]
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