From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (majordomo@vger.kernel.org) by vger.kernel.org via listexpand id S1761026AbYEWAR5 (ORCPT ); Thu, 22 May 2008 20:17:57 -0400 Received: (majordomo@vger.kernel.org) by vger.kernel.org id S1755327AbYEWARr (ORCPT ); Thu, 22 May 2008 20:17:47 -0400 Received: from zcars04e.nortel.com ([47.129.242.56]:43011 "EHLO zcars04e.nortel.com" rhost-flags-OK-OK-OK-OK) by vger.kernel.org with ESMTP id S1755307AbYEWARq (ORCPT ); Thu, 22 May 2008 20:17:46 -0400 Message-ID: <48360D21.9060102@nortel.com> Date: Thu, 22 May 2008 18:17:37 -0600 From: "Chris Friesen" User-Agent: Mozilla Thunderbird 1.0.2-6 (X11/20050513) X-Accept-Language: en-us, en MIME-Version: 1.0 To: Peter Zijlstra CC: "Li, Tong N" , linux-kernel@vger.kernel.org, vatsa@linux.vnet.ibm.com, mingo@elte.hu, pj@sgi.com Subject: Re: fair group scheduler not so fair? References: <4834B75A.40900@nortel.com> <1211439417.29104.7.camel@twins> <4835D14B.20904@nortel.com> <1211486868.6463.134.camel@lappy.programming.kicks-ass.net> <5FD5754DDBA0B1499B5A0B4BB54194850357ED61@fmsmsx411.amr.corp.intel.com> <1211490819.6463.172.camel@lappy.programming.kicks-ass.net> In-Reply-To: <1211490819.6463.172.camel@lappy.programming.kicks-ass.net> Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit X-OriginalArrivalTime: 23 May 2008 00:17:42.0111 (UTC) FILETIME=[6A9A46F0:01C8BC6A] Sender: linux-kernel-owner@vger.kernel.org List-ID: X-Mailing-List: linux-kernel@vger.kernel.org Peter Zijlstra wrote: > Given the following: > > root > / | \ > _A_ 1 2 > /| |\ > 3 4 5 B > / \ > 6 7 > > CPU0 CPU1 > root root > / \ / \ > A 1 A 2 > / \ / \ > 4 B 3 5 > / \ > 6 7 How do you move specific groups to different cpus. Is this simply using cpusets? > > Numerical examples given the above scenario, assuming every body's > weight is 1024: > s_(0,A) = s_(1,A) = 512 Just to make sure I understand what's going on...this is half of 1024 because it shows up on both cpus? > s_(0,B) = 1024, s_(1,B) = 0 This gets the full 1024 because it's only on one cpu. > rw_(0,A) = rw(1,A) = 2048 > rw_(0,B) = 2048, rw_(1,B) = 0 How do we get 2048? Shouldn't this be 1024? > h_load_(0,A) = h_load_(1,A) = 512 > h_load_(0,B) = 256, h_load(1,B) = 0 At this point the numbers make sense, but I'm not sure how the formula for h_load_ works given that I'm not sure what's going on for rw_. Chris