From: Maxim Levitsky <maximlevitsky@gmail.com>
To: linux-kernel@vger.kernel.org
Subject: [Slightly off topic] A question about R/B trees.
Date: Fri, 17 Oct 2008 23:34:50 +0200 [thread overview]
Message-ID: <48F904FA.6090102@gmail.com> (raw)
Hi,
I am working on my small project, and I need a fast container to hold a large sparse array.
Balanced trees seem to fit perfectly.
I decided to implement a red/black tree, and took a look at kernel rb tree for reference,
and I noticed that tree item has no parent pointer, while it seems that it should have it.
I know now that it has parent pointer, but it is mixed with current and parent node colour.
Thus it is assumed that last two bits of this pointer are zero.
I can see anywhere that this restriction is applied.
I see that structure is "aligned" but that I think only ensures that compiler places it
aligned in static data, does the alignment ensures that it will always place it on aligned address in a structure?
But then, the whole container structure can be misaligned, can't it?
Besides a comment there states that alignment is only for CRIS
How about a check for misalignment?
Best regards,
Maxim Levitsky
next reply other threads:[~2008-10-17 21:35 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2008-10-17 21:34 Maxim Levitsky [this message]
2008-10-17 22:15 ` [Slightly off topic] A question about R/B trees Chris Snook
2008-10-17 22:47 ` Maxim Levitsky
2008-10-20 14:54 ` Chris Friesen
2008-10-18 7:53 ` Andi Kleen
2008-10-18 8:45 ` Pekka Enberg
2008-10-20 15:57 ` Maxim Levitsky
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