Re: [PATCH] sched: Make nr_uninterruptible count a signed value

[Michael Wang <wangyun@linux.vnet.ibm.com>]

On 05/09/2012 06:46 AM, Diwakar Tundlam wrote:

>> No that's right. nr_uninterruptible counts the number of tasks in 
>> uninterruptible sleep, so deactivate_task puts a task to sleep, so we 
>> need to increment the number of sleeping tasks, activate_task wakes a 
>> task up so we need to decrement the number of sleeping tasks.
> 
> Yep, I looked at the code for task_contributes_to_load() and I understand what it is all about.
> The ++ and -- are correct, I see it now.
> 
> On the -ve values, strangely inspite of %Ld in the print statement, in my kernel, I see high unsigned values instead of -ve values for nr_uninterruptible.
> 
> But the sum is always 0, though.
> 
> Maybe it is an artifact of 32-bit machine displaying 64-bit print format.
> An (unsigned long)(-24) promoted to (signed long long) ends up as 4294967272.
> As seen in my output of sched_debug.


This may do some help.

Regards,
Michael Wang
---
 kernel/sched/debug.c |    2 +-
 1 files changed, 1 insertions(+), 1 deletions(-)

diff --git a/kernel/sched/debug.c b/kernel/sched/debug.c
index 09acaa1..ab9d53f 100644
--- a/kernel/sched/debug.c
+++ b/kernel/sched/debug.c
@@ -270,7 +270,7 @@ static void print_cpu(struct seq_file *m, int cpu)
                   rq->load.weight);
        P(nr_switches);
        P(nr_load_updates);
-       P(nr_uninterruptible);
+       P((signed long)nr_uninterruptible);
        PN(next_balance);
        P(curr->pid);
        PN(clock);
-- 
1.7.4.1