Re: [RFC 0/5] forced comounts for cgroups.

Glauber Costa
2012-09-05T09:51:54Z

On 09/05/2012 01:45 PM, Tejun Heo wrote:
> Hello,
>
> On Wed, Sep 05, 2012 at 01:31:56PM +0400, Glauber Costa wrote:
>>> > > I simply don't want to have to do two (or more) hierarchy walks for
>>> > > accounting on every schedule event, all that pointer chasing is stupidly
>>> > > expensive.
>> >
>> > You wouldn't have to do more than one hierarchy walks for that. What
>> > Tejun seems to want, is the ability to not have a particular controller
>> > at some point in the tree. But if they exist, they are always together.
> Nope, as I wrote in the other reply,

Would you mind, then, stopping for a moment and telling us what it is,
then, that you envision?