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Message-ID: <50F36352.5080306@gmail.com>
Date: Mon, 14 Jan 2013 09:45:54 +0800
From: Chen Gang F T <chen.gang.flying.transformer@gmail.com>
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To: Guenter Roeck <linux@roeck-us.net>
CC: antoine.trux@gmail.com, fa.linux.kernel@googlegroups.com,
        Johannes Weiner <hannes@saeurebad.de>,
        Linux Kernel Mailing List <linux-kernel@vger.kernel.org>,
        clameter@sgi.com, penberg@cs.helsinki.fi
Subject: Re: Why is the kfree() argument const?
References: <fa.cHMztHfqJXv7vw5O0nQ8SdTrma0@ifi.uio.no> <fa.V9M+5l8C/um5KEiBtZOjbJDQmu4@ifi.uio.no> <379cc523-8f08-4c7f-ae20-20f216352a01@googlegroups.com> <50F26BE0.7020005@gmail.com> <20130113174105.GA24081@roeck-us.net>
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于 2013年01月14日 01:41, Guenter Roeck 写道:
> Maybe the confusion arises from the somewhat lax use of the term "const
> pointer", and the csomewhat confusing way of defining variable attributes in C.
> Strictly speaking,
> 	const char *name;
> which is identical to
> 	char const *name;
> is not a const pointer, it is a pointer to a constant (string in this case).
> A "const pointer", or "constant pointer to an object", would be
> 	char * const name;

  Maybe.

  :-)

-- 
Chen Gang

Flying Transformer

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