From: Dietmar Eggemann <dietmar.eggemann@arm.com>
To: Vincent Guittot <vincent.guittot@linaro.org>,
peterz@infradead.org, mingo@kernel.org,
linux-kernel@vger.kernel.org, pjt@google.com
Cc: yuyang.du@intel.com, bsegall@google.com
Subject: Re: [RFC PATCH] sched: fix hierarchical order in rq->leaf_cfs_rq_list
Date: Wed, 25 May 2016 18:40:11 +0100 [thread overview]
Message-ID: <5745E37B.4080804@arm.com> (raw)
In-Reply-To: <1464083710-4370-1-git-send-email-vincent.guittot@linaro.org>
Hi Vincent,
On 24/05/16 10:55, Vincent Guittot wrote:
> Fix the insertion of cfs_rq in rq->leaf_cfs_rq_list to ensure that
> a child will always called before its parent.
>
> The hierarchical order in shares update list has been introduced by
> commit 67e86250f8ea ("sched: Introduce hierarchal order on shares update list")
>
> With the current implementation a child can be still put after its parent.
>
> Lets take the example of
> root
> \
> b
> /\
> c d*
> |
> e*
>
> with root -> b -> c already enqueued but not d -> e so the leaf_cfs_rq_list
> looks like: head -> c -> b -> root -> tail
>
> The branch d -> e will be added the first time that they are enqueued,
> starting with e then d.
>
> When e is added, its parents is not already on the list so e is put at the
> tail : head -> c -> b -> root -> e -> tail
>
> Then, d is added at the head because its parent is already on the list:
> head -> d -> c -> b -> root -> e -> tail
>
> e is not placed at the right position and will be called the last whereas
> it should be called at the beginning.
>
> Because it follows the bottom-up enqueue sequence, we are sure that we
> will finished to add either a cfs_rq without parent or a cfs_rq with a parent
> that is already on the list. We can use this event to detect when we have
> finished to add a new branch. For the others, whose parents are not already
> added, we have to ensure that they will be added after their children that
> have just been inserted the steps before, and after any potential parents that
> are already in the list. The easiest way is to put the cfs_rq just after the
> last inserted one and to keep track of it untl the branch is fully added.
>
> Signed-off-by: Vincent Guittot <vincent.guittot@linaro.org>
So the use case for this would be you create a multi-level task group
hierarchy on a cpu (e.g. tg_css_id=2,4,6 on cpu=1) and let a task run in
the highest level task group (tg_css_id=6).
list_add_leaf_cfs_rq() call:
...
enqueue_task_fair: cpu=1 tg_css_id=6 cfs_rq=0xffffffc97500f700 on_list=0
enqueue_task_fair: cpu=1 tg_css_id=4 cfs_rq=0xffffffc975175900 on_list=0
enqueue_task_fair: cpu=1 tg_css_id=2 cfs_rq=0xffffffc975866d00 on_list=0
enqueue_task_fair: cpu=1 tg_css_id=1 cfs_rq=0xffffffc97fec44e8 on_list=1
...
In this case, the for_each_leaf_cfs_rq() in update_blocked_averages()
iterates in the tg_css_id=2,1,6,4 order:
...
update_blocked_averages: tg_css_id=2 cfs_rq=0xffffffc975866d00 on_list=1
update_blocked_averages: tg_css_id=1 cfs_rq=0xffffffc97fec44e8 on_list=1
update_blocked_averages: tg_css_id=6 cfs_rq=0xffffffc97500f700 on_list=1
update_blocked_averages: tg_css_id=4 cfs_rq=0xffffffc975175900 on_list=1
...
which I guess breaks the update_tg_cfs_util() call you introduced in
update_blocked_averages() in '[RFC PATCH v2] sched: reflect sched_entity
movement into task_group's utilization'. IMHO, otherwise
update_blocked_averages() can deal with the list not being ordered
tg_css_id=6,4,2,1.
https://lkml.org/lkml/2016/5/24/200
The use of for_each_leaf_cfs_rq() in update_shares() is gone. Do the
remaining call sites (update_runtime_enabled(),
unthrottle_offline_cfs_rqs() require any ordering?
[...]
next prev parent reply other threads:[~2016-05-25 17:40 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2016-05-24 8:55 [RFC PATCH] sched: fix hierarchical order in rq->leaf_cfs_rq_list Vincent Guittot
2016-05-24 9:55 ` Vincent Guittot
2016-05-25 17:40 ` Dietmar Eggemann [this message]
2016-05-26 9:55 ` Vincent Guittot
2016-06-01 12:31 ` Peter Zijlstra
2016-06-01 17:42 ` bsegall
2016-06-02 7:42 ` Vincent Guittot
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